使用linq在xml中动态添加节点

时间:2013-10-23 09:43:23

标签: xml linq linq-to-xml

我想在xml中动态添加节点,文件数组包含大号no。的文件所以我想避免写这个语句新的XElement(“FileName”,files [0])。有没有办法在此语句或任何其他方式上运行for / foreach循环来实现此目标。

string [] sep = { ",",";" };
string[] files = txtFiles.Text.Split(sep, StringSplitOptions.RemoveEmptyEntries);

XDocument xdoc = new XDocument(
                    new XDeclaration("1.0", "utf-16", "true"),
                    new XElement("data",
                        new XElement("rn",
                            new XAttribute("Active", "true"),
                            new XAttribute("Name", txtReportName.Text),   
                        new XElement("Files",
                            new XElement("FileName",files[0]),
                            new XElement("FileName",files[1]),
                            new XElement("FileName",files[2])))));

输出:

<data>
<rn Active="true" Name="testdata">
<Files>
  <FileName>file1</FileName>
  <FileName>file2</FileName>
  <FileName>file3</FileName>
</Files>
</rn>
</data>

1 个答案:

答案 0 :(得分:1)

string [] sep = { ",",";" };
string[] files = txtFiles.Text.Split(sep, StringSplitOptions.RemoveEmptyEntries);

XDocument xdoc = new XDocument(
                    new XDeclaration("1.0", "utf-16", "true"),
                    new XElement("data",
                        new XElement("rn",
                            new XAttribute("Active", "true"),
                            new XAttribute("Name", txtReportName.Text),   
                        new XElement("Files",
                            files.Select(x => new XElement("FileName", x))))));