Question

我正在使用SafeNet的（Alladin）eToken和C＃的PKCS11接口。我需要将没有eToken创建的RSA密钥导入到eToken中。

通过以下方式创建RSA密钥：

RSACryptoServiceProvider RSA = new RSACryptoServiceProvider();
RSAParameters publicKey = RSA.ExportParameters(false);
RSAParameters privateKey = RSA.ExportParameters(true);
eTokenHelper.WritePrivateKeyToToken(session, privateKey, "private");

以及上面WritePrivateKeyToToken的实现是：

public static void WritePrivateKeyToToken(PKCS11.Session session, System.Security.Cryptography.RSAParameters publicParams, string label)
    {

        List<PKCS11.Attribute> attList = new List<PKCS11.Attribute>{};


        attList.Add(new PKCS11.Attribute(PKCS11.CKA_CLASS, PKCS11.CKO_PRIVATE_KEY));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_KEY_TYPE, PKCS11.CKK_RSA));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_PRIVATE, true));
        //attList.Add(new PKCS11.Attribute(PKCS11.CKA_SUBJECT, cert.SubjectName.RawData));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_ID, 0xa1));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_LABEL, label));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_TOKEN, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_MODULUS, publicParams.Modulus));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_PUBLIC_EXPONENT, publicParams.Exponent));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_PRIVATE_EXPONENT, publicParams.D));
        // attList.Add(new ObjectAttribute(PKCS11.CKH_CLOCK, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_MODIFIABLE, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_LOCAL, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_EXTRACTABLE, false));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_NEVER_EXTRACTABLE, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_SENSITIVE, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_ALWAYS_SENSITIVE, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_DERIVE, false));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_LOCAL, false));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_DECRYPT, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_SIGN, true));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_SIGN_RECOVER, false));
        attList.Add(new PKCS11.Attribute(PKCS11.CKA_UNWRAP, false));

        PKCS11.Object.Create(session, attList.ToArray());
    }

当我运行此代码时，我得到代码

的异常

public const int CKR_TEMPLATE_INCONSISTENT = 0x000000D1;

（异常出现在最后一行：Create（））。

在理解我做错了什么的时候，我将不胜感激。

谢谢， RONEN

Answer 1

我有一些问题。顺便说一句，您在代码中设置了两次PKCS11.CKA_LOCAL。它不是核心。不要设置属性PKCS11.CKA_LOCAL - 它会自动设置。如果设置为PKCS11.SENSITIVE，则无法设置CKA_EXTRACTABLE，CKA_NEVER_EXTRACTABLE和CKA_ALWAYS_SENSITIVE。

此代码应该有效：

   List<PKCS11.Attribute> attList = new List<PKCS11.Attribute>{};

    attList.Add(new PKCS11.Attribute(PKCS11.CKA_CLASS, PKCS11.CKO_PRIVATE_KEY));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_KEY_TYPE, PKCS11.CKK_RSA));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_PRIVATE, true));
    //attList.Add(new PKCS11.Attribute(PKCS11.CKA_SUBJECT, cert.SubjectName.RawData));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_ID, 0xa1));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_LABEL, label));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_TOKEN, true));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_MODULUS, publicParams.Modulus));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_PUBLIC_EXPONENT, publicParams.Exponent));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_PRIVATE_EXPONENT, publicParams.D));
    // attList.Add(new ObjectAttribute(PKCS11.CKH_CLOCK, true));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_MODIFIABLE, true));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_SENSITIVE, true));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_DERIVE, false));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_DECRYPT, true));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_SIGN, true));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_SIGN_RECOVER, false));
    attList.Add(new PKCS11.Attribute(PKCS11.CKA_UNWRAP, false));

    PKCS11.Object.Create(session, attList.ToArray());

Aladdin eToken因导入RSA密钥而失败

1 个答案: