Question

我正在尝试从main方法参数列表创建一个Boat对象数组，然后使用.name将args数组中给出的名称赋值给boat。格式化这个的正确方法是什么？

public static void main(String[] args) {
    for(int i = 0; i < args.length; i++){
        Boat args[i] = new Boat();
        args[i].name = args[i];
    }
}

Answer 1

Boat boat = new Boat();
boat.name = args[i];
// and then do something with the Boat, I guess...

Answer 2

当你这样做时

for(int i=0; i<args.length; i++) { Boat
    args[i] = new Boat();

你遇到了范围问题。您需要更改Boat数组的名称并在循环外声明它（因此它只创建一次）。

Boat armada[args.length];
for(int i = 0; i < args.length; ++i) {
    armada[i] = new Boat();
    armada[i].name = args[i];
}

Answer 3

public static void main(String[] args) {
  Boat[] boats = new Boat[args.length];
  for (int i=0; i< args.length; i++) {
    boats[i] = new Boat();
    boats[i].name = args[i];
  }
}

我假设您的Boat班级有一个public字段，名为name。

Answer 4

首先，您需要创建船只阵列

Boat[] boats = new Boat[args.length];

然后，遍历args获取名称，并为每个名称创建一个名为的新船并将其保存在船只阵列的位置

for(int i = 0; i < args.length; i++){
    Boat boat = new Boat(); //Create new boat
    boat.name = args[i]; //Give the name to the new boat
    boats[i] = boat; //And save it into the array
}

Answer 5

Add a new constructor which accepts name as argument and try the following


        Boat[] boat = new Boat[args.length]; 
            for (int iter = 0; iter < args.length; iter++) {
                boat[iter] = new Boat(args[iter]);
        }

格式化Java for循环

5 个答案: