我确信这很简单,我只是错过了一些简单但......
我有一个主页(index.html),我想链接到另一个页面,它是一个.xsl文件(显示一些xml数据)。我正在使用此代码来执行此操作:
<h1><a href="catalogue_overview.xsl">VIEW CATALOGUE</a></h1>
当我单独打开.xsl文件(我使用Dreamweaver)时,它会打开并显示数据(来自xml文件)。
当我从index.html页面上的链接打开它时,它只显示<h>
和<p>
标签中包含的未格式化文本等。没有格式化,也没有xml数据。< / p>
我做错了什么?
我是否需要告诉index.html文件,以便了解.xsl文件?
我这样做错了吗?
我以相同的方式链接到PHP文件,似乎工作正常。
如果有帮助,我会发布我的代码!
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="catalogue_overview.xsl"?>
<catalogue>
<record>
<catId>001</catId>
<title>Fungus</title>
<location>NP</location>
<photographer>Me</photographer>
<equipment>Canon EOS 40D</equipment>
<caption>Small fungus of the genus Fungaroidiae on a log</caption>
<notes>This is a very rare species of fungus</notes>
<date>10/8/2012</date>
<imageUrl>images/IMG_1684.jpg</imageUrl>
</record>
</catalogue>
<?xml version="1.0" encoding="UTF-8"?><!-- DWXMLSource="catalogue.xml" -->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="UTF-8"/>
<xsl:template match="catalogue">
<html>
<head>
<title>Photo Catalogue</title>
<link rel="stylesheet" type="text/css" href="css/style.css"/>
</head>
<body>
<h1 align="center"> Photo Catalogue</h1>
<h2 align="center"> Catalogue Overview </h2>
<p align="center"> This is an overview of the photo catalogue. It enables the user to have a quick and easy browse through the images and their information.</p>
<hr/>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="catId">
<h2> Catalogue ID: <span style="color:2A588F"><xsl:apply-templates/> </span> </h2>
</xsl:template>
<xsl:template match="title">
<h3> Title: <span style="color:2A588F"><xsl:apply-templates/> </span> </h3>
</xsl:template>
<xsl:template match="location">
<p> Location: <span style="color:2A588F"><xsl:apply-templates/> </span> </p>
</xsl:template>
<xsl:template match="photographer">
<p> Photographer: <span style="color:2A588F"><xsl:apply-templates/> </span> </p>
</xsl:template>
<xsl:template match="equipment">
<p> Equipment: <span style="color:2A588F"><xsl:apply-templates/> </span> </p>
</xsl:template>
<xsl:template match="caption">
<p> Caption: <span style="color:2A588F"><xsl:apply-templates/> </span> </p>
</xsl:template>
<xsl:template match="notes">
<p> Notes: <span style="color:2A588F"><xsl:apply-templates/> </span> </p>
</xsl:template>
<xsl:template match="date">
<p> Date: <span style="color:2A588F"><xsl:apply-templates/> </span> </p>
</xsl:template>
<xsl:template match="imageUrl">
<p>Image:<br/><img src="{.}" width="250"/></p>
<hr/>
</xsl:template>
</xsl:stylesheet>
<!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>Photo Catalogue - HOME</title>
<link rel="stylesheet" type="text/css" href="css/style.css"/
</head>
<body>
<div class="container">
<div class="content">
<h1>Photo Catalogue</h1>
<h2>Welcome to the Photo Catalogue</h2>
<p>It is intended to be a simple tool to store you favourite photos for easy viewing. It uses XML to store the image details and this is retrieved, displayed and edited using a combination of XSL and PHP.</p>
<h2>Navigation</h2>
<p>Select the option you would like below to see its functionality...</p>
<h1><a href="catalogue_overview.xsl">VIEW CATALOGUE</a></h1>
<h1><a href="catalogueupdate.php">EDIT CATALOGUE</a></h1>
</div>
</div>
</body>
</html>
希望这有帮助
注意.php文件的链接似乎工作正常。我正在逃避XAMPP。
由于
答案 0 :(得分:2)
您应该链接到应该呈现数据的XML文件。这意味着您的INDEX.HTML更改
<h1><a href="catalogue_overview.xsl">VIEW CATALOGUE</a></h1>
到
<h1><a href="catalogue.xml">VIEW CATALOGUE</a></h1>
然后,XML文件通过
引用XSL样式表<?xml-stylesheet type="text/xsl" href="catalogue_overview.xsl"?>