Question

我使用以下函数使用SearchDisplayController进行搜索

- (void)handleSearchForTerm:(NSString *)searchTerm{

[self.searchResults removeAllObjects]; // First clear the filtered array.

FMDatabase *db = [FMDatabase databaseWithPath:[Utility getDatabasePath]];


[db open];


FMResultSet *results = [db executeQuery: [NSString stringWithFormat:@"SELECT * FROM periods where (searchstartyear <= %@)  AND (searchendyear >= %@)", searchTerm, searchTerm]];

    NSMutableArray *array = [[NSMutableArray alloc] init ];
    [array removeAllObjects];
    while ([results next]) {
        Periods *searchPeriod = [[Periods alloc] init];
        searchPeriod.periodname = [results stringForColumn:@"PeriodName"];
        searchPeriod.startyear = [results stringForColumn:@"StartYear"];
        searchPeriod.endyear = [results stringForColumn:@"EndYear"];
        searchPeriod.thumb = [results stringForColumn:@"Thumb"];
        searchPeriod.childid = [results stringForColumn:@"ChildID"];
        [array addObject:searchPeriod];           
    }
    [self.searchResults addObject:array];


[db close];}

期间是一个对象

#import <UIKit/UIKit.h>

@interface Periods : NSObject

@property (nonatomic,strong) NSString *periodname;
@property (nonatomic,strong) NSString *startyear;
@property (nonatomic,strong) NSString *endyear;
@property (nonatomic,strong) NSString *thumb; 
@property (nonatomic,strong) NSString *childid;


@end

我得到NSInvalidArgumentException - 在执行以下代码时发送到实例的无法识别的选择器：

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"PeriodsCell";

    UITableViewCell *cell = [self.mainTableView dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
    }

    // Configure the cell...

    if (tableView != [[self searchDisplayController] searchResultsTableView])
    {

        NSMutableArray *array = [periodsdataarray objectAtIndex:indexPath.section];
        NSMutableDictionary *dictionary = [array objectAtIndex:indexPath.row];




        UILabel *childIDLabel = (UILabel *)[cell viewWithTag:999];
        childIDLabel.text = [dictionary valueForKey:@"ChildID"];
        UILabel *titleLabel = (UILabel *)[cell viewWithTag:100];
        titleLabel.text = [dictionary valueForKey:@"PeriodName"];


        UILabel *previewLabel = (UILabel *)[cell viewWithTag:101];
        previewLabel.text = [NSString stringWithFormat:@"%@ - %@",[dictionary valueForKey:@"StartYear"],[dictionary valueForKey:@"EndYear"]];
        UIImageView *imageview = (UIImageView *)[cell viewWithTag:102];
        [imageview setImage:[UIImage imageNamed:[dictionary valueForKey:@"Thumb"]]];
    }
    else
    {
        Periods *periodcell = [self.searchResults objectAtIndex:indexPath.row];

        cell.tag = 666;
        UILabel *childIDLabel = (UILabel *)[cell viewWithTag:999];
        childIDLabel.text = periodcell.childid;
        UILabel *titleLabel = (UILabel *)[cell viewWithTag:100];
        titleLabel.text = periodcell.periodname;


        UILabel *previewLabel = (UILabel *)[cell viewWithTag:101];
        previewLabel.text = [NSString stringWithFormat:@"%@ - %@",periodcell.startyear,periodcell.endyear];
        UIImageView *imageview = (UIImageView *)[cell viewWithTag:102];
        [imageview setImage:[UIImage imageNamed:periodcell.thumb]];


    }

    return cell;
}

...更具体地说，当执行此行时：

childIDLabel.text = periodcell.childid;

我做错了什么？

Answer 1

我所犯的错误是在handleSearchForTerm函数。

我正在使用NSMutableArray *数组来保存我的Periods对象的值，然后我将数组添加到我的searchResults数组中（期望searchResults持有Periods）。解决方案就像将Periods直接添加到我的searchResults数组并完全放弃数组一样简单......

NSInvalidArgumentException - 发送到实例的无法识别的选择器

1 个答案: