Question

我有一个查询，我试图在SQL Server 2008中编写一个这样的行：

quoteID | dateEntered | insuredName | agentName | quoteType | status | noteDate | userType

我目前有：

SELECT
    t1.quoteID,
    t1.dateEntered,
    t1.insuredFirstName + ' ' + t1.insuredLastName as insuredName,
    t2.FirstName + ' ' + t2.LastName as agentName,
    t1.quoteType,
    t1.status,
    t3.noteDate
FROM
    quote_genericInformation t1

INNER JOIN tbl_agents t2
    ON t1.createUserID = t2.AgentNumber

INNER JOIN 
    (SELECT quoteID, MAX(dateEntered) as noteDate
        FROM quote_notes GROUP BY quoteID) t3
    ON t1.quoteid = t3.quoteid

ORDER BY t1.quoteID

这会产生如下结果：

quoteID | dateEntered | insuredName | agentName     | quoteType | status | noteDate
54      | 01/01/2000  | First Last  | First Last    | apptype   | open   | 01/01/2000

我需要将usertype添加为另一列，但是当我添加它时，我开始重复。
无论是否存在quoteID的<_ li>，我都需要这一行来显示一行
我需要这个来显示笔记中的最新usertype（基于注释）

谢谢！

Answer 1

回答问题2：如果你想要返回一行，你应该使用LEFT OUTER JOIN而不是INNER JOIN。有关联接类型的说明，请参阅Wikipedia：http://en.wikipedia.org/wiki/Join_(SQL)

关于usertype的问题：我们需要有关数据库模式的更多信息。顺便说一下，我建议为你的别名使用一致的命名（比如员工e和人员p，而不是t1，t2等）。这使得查询更具可读性恕我直言。

Answer 2

WITH note AS (
    SELECT quoteID
        , dateEntered as noteDate 
        , usertype 
        , ROW_NUMBER() OVER (PARTITION BY quoteID ORDER BY dateEntered DESC) as row_num
    FROM quote_notes
)
SELECT
    t1.quoteID,
    t1.dateEntered,
    t1.insuredFirstName + ' ' + t1.insuredLastName as insuredName,
    t2.FirstName + ' ' + t2.LastName as agentName,
    t1.quoteType,
    t1.status,
    t3.noteDate,
    t3.usertype
FROM
    quote_genericInformation t1

INNER JOIN tbl_agents t2
    ON t1.createUserID = t2.AgentNumber
LEFT JOIN note t3
    ON t1.quoteid = t3.quoteid
    AND t3.row_num = 1
ORDER BY t1.quoteID

Answer 3

选择 t1.quoteID， t1.dateEntered， t1.insuredFirstName + t1.insuredLastName作为InsuredName， t2.FirstName + t2.LastName作为AgentName， t1.quoteType， t1.status， t3.noteDate， t3.usertype 从 quote_genericInformation t1 INNER JOIN tbl_agents t2 ON t1.createUserID = t2.AgentNumber LEFT JOIN注意事项t3 ON t1.quoteid = t3.quoteid AND t3.row_num = 1 ORDER BY t3.noteDate desc

如何将4个表与连接和最大值组合在一起

3 个答案: