Question

我正在使用MS Access运行一些计算。以下是给我带来麻烦的整体代码：

Dim cmd3 As OleDbCommand = New OleDbCommand("INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) _
SELECT ?, ?, (M * 0) + B _AS Tier_Juncture_1, _
((Avg(C." & Calculation & " * G.Growth) - Avg(C." & Calculation & ") * Avg(G.Growth)) / (StDevP(C." & Calculation & ") * StDevP(G.Growth)) * 10) AS Weight _
FROM (Sum(G.Growth) / Count(*)) - (1 * (Sum(C." & Calculation & ") / Count(*))) AS B, _
(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth)) / Count(*))) / (Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ") / Count(*)))) AS M, _
" & Calculation & " AS C INNER JOIN " & Growth_Rate & " AS G _
" & On_Statement & "", con)
    cmd3.Parameters.AddWithValue("@Calculation", Calculation)
    cmd3.Parameters.AddWithValue("@[Interval]", Interval)
    cmd3.ExecuteNonQuery()

更具体地说，我的目标是将此公式的结果插入到Criteria字段中名为Tier_Juncture_1的表中：

(M * 0) + B _AS Tier_Juncture_1

正如您所看到的，我在此等式中有两个变量，M和B。以下是每个公式：

(Sum(G.Growth) / Count(*)) - (1 * (Sum(C." & Calculation & ") / Count(*))) AS B

(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth)) / Count(*))) / (Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ") / Count(*)))) AS M

我的问题是，在我的SQL语句中，我是否将我的两个变量的公式放在我Tier_Juncture_1的原始公式可以使用变量的位置？如上所示，我尝试将它们放入我的FROM子句中，但我收到此错误：Syntax error in FROM clause.

变量本身的公式应该没有任何问题。我已经独立测试了它们，它们都返回正确的值而没有错误。我只需要知道将它们放在我的SQL语句中的哪个位置。

更新

根据以下建议，我已从SQL语句中删除了参数。它现在看起来像这样：

Dim cmd3 As OleDbCommand = New OleDbCommand("INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) _
SELECT " & Calculation & ", " & Interval & ", (M * 0) + B AS Tier_Juncture_1, _
((Avg(C." & Calculation & " * G.Growth) - Avg(C." & Calculation & ") * Avg(G.Growth)) / (StDevP(C." & Calculation & ") * StDevP(G.Growth)) * 10) AS Weight _
FROM (Sum(G.Growth) / Count(*)) - (1 * (Sum(C." & Calculation & ") / Count(*))) AS B, _
(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth)) / Count(*))) / (Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ") / Count(*)))) AS M, _
" & Calculation & " AS C INNER JOIN " & Growth_Rate & " AS G _
" & On_Statement & "", con)
    cmd3.ExecuteNonQuery()

但是当我运行此操作时，我收到以下错误：Syntax error in FROM Clause.

我相信我收到此错误是因为我从原始帖子中插入了变量M和B的等式。所以我的问题仍然存在。我在哪里将这些方程放在我的SQL语句中。

第二次更新

以下是Debug.Writeline(cmd3.CommandText)返回的SQL语句：

INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) SELECT Current_Ratio, MRQ, (M * 0) + B AS Tier_Juncture_1, ((Avg(C.Current_Ratio * G.Growth) - Avg(C.Current_Ratio) * Avg(G.Growth)) / (StDevP(C.Current_Ratio) * StDevP(G.Growth)) * 10) AS Weight FROM (Sum(G.Growth) / Count(*)) - (1 * (Sum(C.Current_Ratio) / Count(*))) AS B, (Sum(C.Current_Ratio * G.Growth) - ((Sum(C.Current_Ratio) * Sum(G.Growth)) / Count(*))) / (Sum(C.Current_Ratio * C.Current_Ratio) - ((Sum(C.Current_Ratio) * Sum(C.Current_Ratio) / Count(*)))) AS M, Current_Ratio AS C INNER JOIN Quarterly_Growth_Rates AS G ON (C.Ticker = G.Ticker) AND ((IIF(C.Period = 4, C.Year + 1, C.Year)) = G.Year) AND ((IIF(C.Period = 4, 1, C.Period + 1)) = G.Qtr)

Answer 1

为了在您的SQL Avg(G.Growth)中返回非聚合字段和聚合函数，您必须使用GROUP BY。

通过查看您的代码，我知道Calculation不是聚合，因为您对字段和表名使用相同的变量。

如果您需要进一步的帮助，您需要提供生成的SQL以供检查，我们不知道您的变量中有什么。 IE，Debug.Writeline(cmd3.CommandText)

在SQL语句中放置变量方程的位置？

1 个答案: