Question

Model   Icolor

m1  i1

m1  i2

m1  i3

m2  i2

m2  i3

m2  i4

我有一个这样的表，我需要选择Icolor值，这对m1和m2都是常见的。

Answer 1

DECLARE @TABLE TABLE
(
    Model VARCHAR(30),
    LColour VARCHAR(30)
)

INSERT INTO @TABLE 
SELECT 'm1','i1' UNION
SELECT 'm1','i2' UNION
SELECT 'm1','i3' UNION
SELECT 'm2','i2' UNION
SELECT 'm2','i3' UNION
SELECT 'm2','i4' 

SELECT 
    LColour
FROM 
    @TABLE
GROUP BY 
    LColour
HAVING 
    COUNT(*) = (SELECT COUNT(DISTINCT Model) FROM @TABLE)

编辑以提供每种型号通用的所有颜色：）

Answer 2

更新：

select color from 
  (select color, T2.num from test_table, 
     (select count(*) as num from (select distinct model from test_table) T) T2
group by color, T2.num
having count(*) = T2.num) T3

Answer 3

我认为它应该是这样的：

SELECT tt.Icolor
FROM test_table tt
INNER JOIN test_table tt1 ON tt1.Icolor = tt.Icolor AND tt1.Model = 'm2'
WHERE tt.Model = 'm1'

Answer 4

select lcolor from Model where m1 = x
union 
select lcolor from Model where m2 = y

x是您的模型m1，y是您的模型m2值，或者如果它是一个数据类型，那么您在那里得到1。 union从两个查询的结果中获取共享值。我不确定语法是否正确（但我很确定它是）。如果没有，你可以谷歌。

选择查询以检索公共数据

4 个答案: