SQLite 3 - 如何从下面的代码中选择MIN（）中的下一个值..以及如何为所有next，next ...值自动化它

Question

               MIN( CASE
                    WHEN Type = 435 THEN TimeStamp 
               END ) AS InTime,                   
               MIN( CASE
                    WHEN Type = 324 THEN TimeStamp 
               END ) AS OutTime

上面的代码使用min（）来查找最小值，如何找到下一个最小值以及如何获取所有下一个....值...

Answer 1

SELECT TimeStamp AS InTime
FROM MyTable
WHERE Type = 435
ORDER BY Timestamp;

SELECT TimeStamp AS OutTime
FROM MyTable
WHERE Type = 324
ORDER BY Timestamp;