Question

我在armhf ubuntu目标（arm9，omap4）上遇到了以下问题。我正在尝试使用Ubuntu 12.04 arm-linux-gnueabihf工具链来执行maliit键盘。我成功地交叉编译的Qt5和maliit-framework使用的不同库，但是当执行maliit-server或maliit-exampleapp-plainqt时，它在动态库打开后立即退出。这是strace输出的结束：

open("/mnt/internal/library/icu_4.8.1.1/lib/libicudata.so.48", O_RDONLY|O_CLOEXEC) = 3
read(3, "\177ELF\1\1\1\0\0\0\0\0\0\0\0\0\3\0(\0\1\0\0\0T\2\0\0004\0\0\0"..., 512) = 512
lseek(3, 18280604, SEEK_SET)            = 18280604
read(3, "\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0"..., 480) = 480
lseek(3, 18280460, SEEK_SET)            = 18280460
read(3, "A \0\0\0aeabi\0\1\26\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4,"..., 33) = 33
exit_group(1)                           = ?
+++ exited with 1 +++

我首先认为它与不同库之间的arm浮点不兼容有关，但是库上的readelf -h给了我这个（除了其中一些有Tag_ABI_optimization_goals：Aggressive Speed）：

Attribute Section: aeabi
File Attributes
  Tag_CPU_name: "7-A"
  Tag_CPU_arch: v7
  Tag_CPU_arch_profile: Application
  Tag_ARM_ISA_use: Yes
  Tag_THUMB_ISA_use: Thumb-2
  Tag_FP_arch: VFPv3-D16
  Tag_ABI_PCS_wchar_t: 4
  Tag_ABI_FP_denormal: Needed
  Tag_ABI_FP_exceptions: Needed
  Tag_ABI_FP_number_model: IEEE 754
  Tag_ABI_align_needed: 8-byte
  Tag_ABI_align_preserved: 8-byte, except leaf SP
  Tag_ABI_enum_size: int
  Tag_ABI_HardFP_use: SP and DP
  Tag_ABI_VFP_args: VFP registers
  Tag_CPU_unaligned_access: v6
  Tag_DIV_use: Not allowed

我可以通过strace看到已找到所有库。在strace上获得“aeabi”给出了以下输出：

read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\3\f"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A4\0\0\0aeabi\0\1*\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 53) = 53
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A \0\0\0aeabi\0\1\26\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4,"..., 33) = 33

ldd也退出而不显示所需的所有不同库并返回1.

有谁知道这里发生了什么？

ldd在armhf目标上退出并出错

0 个答案: