Question

我的Xml看起来像这样：

biometrictDate, biometricID,dateOfBirth, firstName, gender, 
lastName, consumerUserId, MedicalHeightValue

是表格中的所有列。

<Assessment biometrictDate="20120305 08:03:00" biometricID="74330759" 
            dateOfBirth="1975-04-08" firstName="BRYAN" gender="M" lastName="HAYES" 
            consumerUserId="120004223500"> 
    <HealthAttribute>
        <Identifier>MedicalHeightValue</Identifier>
        <Value>67</Value>
    </HealthAttribute>
</Assessment>

MedicalHeightValue应单独放在使用以下查询完成的HealthAttribute代码之间：

select C.Value, C.Identifier
from TableA
    outer apply (values
        ('MedicalHeightValue', MedicalHeightValue) ) as C(Identifier, Value)
for xml path('HealthAttribute')

现在我想在评估标记

中单独使用以下列

{biometrictDate, biometricID, dateOfBirth, firstName, gender, lastName, consumerUserId}

请帮忙吗？

新XML应如下所示：

<Assessment biometrictDate="20120305 08:03:00" biometricID="74330759" 
            dateOfBirth="1975-04-08" firstName="BRYAN" gender="M" lastName="HAYES" 
            consumerUserId="120004223500"> 
   <HealthAttribute> 
      <Identifier>MedicalHeightValue</Identifier> 
      <Value>67</Value> 
   </HealthAttribute> 
</Assessment>

Answer 1

首先，真的很难理解你想要得到什么。我想我已经从你的问题和你的pervious question中找到了这个问题（顺便说一句，BTW仍然没有接受答案）。

以下是您需要的查询：

select
    A.biometrictDate, A.biometricID, A.dateOfBirth,
    A.firstName, A.gender, A.lastName, A.consumerUserId,
    (
        select *
        from (values
            ('MedicalHeightValue', A.MedicalHeightValue),
            ('MedicalWeightValue', A.MedicalWeightValue)
        ) as V(Identifier, Value)
        for xml path('HealthAttribute'), type
    )
from table1 as A
for xml raw('Assessment')

您也可以这样做，以便更好地控制名称：

select
    A.biometrictDate as [@biometrictDate],
    A.biometricID as [@biometricID],
    A.dateOfBirth as [@dateOfBirth],
    A.firstName as [@firstName],
    A.gender as [@gender],
    A.lastName as [@lastName],
    A.consumerUserId as [@consumerUserId],
    (
        select *
        from (values
            ('MedicalHeightValue', A.MedicalHeightValue),
            ('MedicalWeightValue', A.MedicalWeightValue)
        ) as V(Identifier, Value)
        for xml path('HealthAttribute'), type
    )
from table1 as A
for xml path('Assessment')

<强> sql fiddle demo

使用sql查询形成XML标记

1 个答案: