Question

假设我已将JSON发布到服务器，如下所示：

{
    warFile: {name: "test1", dependencies: [test0, test2]},
    param: {build: true, test: true}
}

我有3节课如下：

public class WarFile{
   private String name:
   private String[] dependencies;
   public void setName(){...};
   public String getName(){...};
   public void setDependencies(){...};
   public String[] getDependencies(){...};
}

public class Param{
   private boolean build;
   private boolean test;
   public void setBuild(){...};
   public boolean isBuild(){...};
   public void setTest(){...};
   public boolean isTest(){...};
}

public class Command{
    private WarFile warFile;
    private Param param;
    private void setWarFile(){...};
    private WarFile getWarFile(){...};
    private void setParam(){...};
    private Param getParam(){...};
}

控制器如下：

@RequestMapping(value = "/test.ajax", method = RequestMethod.POST)
public @ResponseBody
BuildResult buildWar(@RequestBody Command cmd) {
    return logic.build(cmd.getWarFile(), cmd.getParam());
}

由于Command中的warFile和param不是基本类型，我总是会收到以下错误：

The request sent by the client was syntactically incorrect.

如果Command中的所有属性都是基本类型，我确信没有任何问题。但是这个错误怎么会发生呢？我的意思是，对象很简单，不需要为它们编写自定义反序列化器。

Answer 1

您的请求映射是否是/ html <form>中的/test.ajax或/ test？

您是否添加了jackson mapper jar依赖项？如果是，下一个解决方案将逃脱你的报价我想。这可能有所帮助 Spring MVC : The request sent by the client was syntactically incorrect

Getting HTTP status 400 - The request sent by the client was syntactically incorrect: using curl to post/put json request

Answer 2

“发送给客户端的请求在语法上是不正确的”意味着您发送的请求的内容有问题，不一定是您的控制器或Spring配置。首先，您的JSON无效。杰克逊无法正确地将JSON映射到它应该代表的对象。它应该是：

{
    "warFile": {
        "name": "test1",
        "dependencies": ["test0", "test2"]
    },
    "param": {
        "build": true,
        "test": true
    }
}

其次，确保内容类型为application / json。最后，为什么你的Command对象有私有的getter / setter，你的setter没有字段参数？

如何使用spring mvc将json反序列化为复杂的对象？

2 个答案: