如何搜索确切的数字
这段代码就像这样工作
如果我搜索24626838(这是完全没有)它没有显示任何内容
之后如果我搜索这个没有2462683(这不是完整的否)
所以它显示了这样的结果
像这样24626838
24626838
24626836
24626832
24626837
我希望得到像这样的结果
如果我搜索这个没有24626838(这是完整的否)
所以它显示的确如此
24626838
24626838
我该怎么做才能帮我解决这个问题
,这是代码
<?php
//connect to database
mysql_connect('localhost','root','');
mysql_select_db('member');
$alphabet = array('A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z');
foreach ($alphabet as $letter) {
echo "<a href=\"viewuser.php?letter=" . $letter . "\" class=\"style2\">" . $letter . "</a> | ";
}
echo "<br>";
echo "<a href=\"index.php?\" class=\"style2\">Show All</a></p><br /> <form method=\"post\" action=\"?\">
<input type=\"hidden\" name=\"letter\" value=\"{$_GET['letter']}\" />";
$page = (empty($_GET['page'])) ? 1 : $_GET['page'];
$letter = (empty($_GET['letter'])) ? "%" : $_GET['letter'];
$name = (empty($_GET['name'])) ? "%male" : $_GET['name'];
?></td>
</tr>
<p>
<?php
//get date
$button = $_GET['submit'];
$search = $_GET['search'];
$s = $_GET['s'];
if (!$s)
$s = 0;
$e = 12;
$next = $s + $e; $prev = $s - $e;
if (strlen($search)<=1)
echo "";
else
{
echo "<class=\"style2\"> You searched for <b>$search</b>";
//connect to database
mysql_connect('localhost','root','');
mysql_select_db('member');
//explode search term
$search_exploded = explode(" ",$search);
foreach($search_exploded as $search_each)
{
$str = mysql_real_escape_string(substr($search_each, 0, 9));
//construct query
$x++;
if ($x==1) $construct .= "number LIKE '$str%'";
}
//echo out construct
$construct = "SELECT * FROM workorder WHERE $construct";
$run = mysql_query($construct);
$foundnum = mysql_num_rows($run);
if ($foundnum==0)
echo "<class=\"style2\">No user found.";
else
{
?>
<?php
echo "<class=\"style2\"><p>$foundnum results found.</p>";
while ($runrows = mysql_fetch_assoc($run))
{
echo "<table class='hovertable' border='1' cellpadding='0' cellspacing='0'>";
echo "<tr><th>User name</th><th>Number</th><th>Exchange</th><th>Cabnint</th><th>Service</th><th>Open Date</th><th>Close Date</th><th>Remaks</th><th>Status</th><th>Edit</th><th>Detail</th><th>Delete</th></tr>";
if ($runrows > 0) {
while($runrows = mysql_fetch_array($run)) {
echo "<tr><td>";
echo $runrows['username'];
echo "</td><td>";
echo $runrows['number'];
echo "</td><td>";
echo $runrows['exchange'];
echo "</td><td>";
echo $runrows['cabnint'];
echo "</td><td>";
echo $runrows['service'];
echo "</td><td>";
echo $runrows['opendate'];
echo "</td><td>";
echo $runrows['closedate'];
echo "</td><td>";
echo $runrows['remaks'];
echo "</td><td>";
echo $runrows['status'];
echo "</td><td>";
echo '<a href="edit.php?id=' . $runrows['id'] . '" class="style2">Edit</a>';
echo "</td><td>";
echo '<a href="detail.php?id=' . $runrows['id'] . '" class="style2">Detail</a>';
echo "</td><td>";
echo '<a href="delete.php?id=' . $runrows['id'] . '" class="style2">Delete</a>';
echo "</td></tr>";
}
} else {
echo "<tr><td colspan=\"5\">No results found!</td></tr>";
}
echo "</table>";
}
}
}
?>
答案 0 :(得分:0)
如果您要搜索确切的数字,请使用column='$number'
代替column LIKE $number
。在WHERE
子句中,我建议将偶数括在单引号中,因为我最近遇到的问题是使用WHERE column = 1234
这也与12345
匹配,但WHERE column = '1234'
匹配只有非常确切的数字。
答案 1 :(得分:0)
我想问题出在这里:
number LIKE '$str%'
不要那样用。相反,尝试这样:
number = '$str'
因此它执行严格的SELECT
而不是搜索。当你给%
时,可能会有其他东西存在(或者不存在,我不确定)。
此外,将LIKE
用于数字并不是一个好主意。这只是一个建议。
答案 2 :(得分:0)
应该可以试试这个
if ($x==1) $construct .= "number LIKE '".$str."%'";