我希望有人可以帮助我。如果我做标准的内部加入或右加入,我得到的结果很少。也很高兴也知道我为什么不会工作。
我有一个主要的成员表。 MemberID对所有表格都是通用的
Select * from apf_members
MemberID--|--AppsTitle--|--AppsFirstName--|--AppsLastName-- 2015 Mrs Naomi Specter 2016 Mr Marisa Watson 2025 Mr Elia Barker 2031 Dr Heth Rowing 2044 Ms Kathryn McKenzie
我还想附加3个动态构建的额外列。
--CurrentMember--|--UnrenewedMember--|--LapsedMember--
以下查询目前仅返回值~IF~用户有记录。我需要它返回NULL或空字符串。
@theDate是一个变量,暂时将其分配给Getdate。
Declare @theDate date
SET @theDate = GetDate()
Select Description as 'CurrentMember' from apf_finances
where @theDate between StartDate and EndDate
and Status = 'Financial Status'
Select Description as 'UnrenewedMember'
from apf_finances
where @theDate between DATEADD(year, -1, StartDate) and DATEADD(year, -1, EndDate)
and Status = 'Financial Status'
Select Description as 'LapsedMember'
from apf_finances
where @theDate between DATEADD(year, -2, StartDate) and DATEADD(year, -2, EndDate)
and Status = 'Financial Status'
放在一起,最终结果看起来像这样。
MemberID--|--AppsTitle--|--AppsFirstName--|--AppsLastName--|--CurrentMember--|--UnrenewedMember--|--LapsedMember-- 2015 Mrs Naomi Specter f nf nf 2016 Mr Marisa Watson uf NULL nf 2025 Mr Elia Barker NULL NULL NULL 2031 Dr Heth Rowing co exp f 2044 Ms Kathryn McKenzie NULL f NULL
* 更新22/10/2013 *
这是一个应该重新创建表的SQL脚本
CREATE TABLE [dbo].[apf_Members](
[MemberID] [int] IDENTITY(1,1) NOT NULL,
[AppsTitle] [nvarchar](50) NULL,
[AppsFirstName] [nvarchar](50) NULL,
[AppsMiddleName] [nvarchar](50) NULL,
[AppsLastName] [nvarchar](50) NULL,
)
GO
CREATE TABLE [dbo].[apf_Finances](
[ID] [int] IDENTITY(1,1) NOT NULL,
[MemberID] [int] NOT NULL,
[Description] [nvarchar](50) NULL,
[StartDate] [date] NULL,
[EndDate] [date] NULL,
[Status] [nvarchar](50) NULL
)
GO
SET IDENTITY_INSERT dbo.[apf_Members] ON
GO
SET IDENTITY_INSERT dbo.[apf_Finances] ON
GO
INSERT INTO [dbo].[apf_Members]
([MemberID],[AppsTitle],[AppsFirstName],[AppsLastName])
VALUES (2015,'Mrs','Naomi', 'Specter' ),
(2016 , 'Mr' ,'Marisa','Watson' ),
(2025 , 'Mr' ,'Elia','Barker'),
(2031 , 'Dr','Heth','Rowing'),
(2044 , 'Ms','Kathryn','McKenzie');
INSERT INTO [apf_Finances]
([ID], [MemberID], [Description], [StartDate], [EndDate], [Status] )
VALUES
(12381, 2016, 'f' ,'2013-10-15','2014-10-14','Financial Status'),
(12382, 2016, '' ,'2013-10-15','2014-10-14','Donation'),
(12361, 2025, 'f' ,'2013-10-12','2014-10-11','Financial Status'),
(12362, 2025, '' ,'2013-10-12','2014-10-11','Donation'),
(12357, 2031, 'f' ,'2013-10-11','2014-10-10','Financial Status'),
(12358, 2031, '' ,'2013-10-11','2014-10-10','Donation'),
(12379, 2044, 'f' ,'2012-10-21','2013-10-20','Financial Status'),
(12380, 2044, '' ,'2012-10-21','2013-10-20','Donation'),
(12377, 2016, 'f' ,'2012-10-17','2013-10-16','Financial Status'),
(12378, 2016, '' ,'2012-10-17','2013-10-16','Donation'),
(12373, 2025, 'f' ,'2012-10-16','2013-10-15','Financial Status'),
(12374, 2031, '' ,'2011-10-16','2013-10-15','Donation'),
(12375, 2031, 'f' ,'2011-10-16','2013-10-15','Financial Status'),
(12376, 2044, '' ,'2011-10-16','2013-10-15','Donation'),
(12371, 2044, 'f' ,'2011-10-15','2013-10-14','Financial Status');
答案 0 :(得分:1)
这是一个Northwind示例。
您可以使用派生表“过滤”。 然后在派生表上保持联接。
你可以写你的,你将有3个派生表。
derivedCurrentMember derivedUnrenewedMember derivedLapsedMember
将过滤/逻辑放在每个派生表中。然后在每一个上加入。
这是一个通用的Northwind示例。
我的“过滤逻辑”是否存在折扣。 (innerOd1.Discount< = 0和innerOd1.Discount> 0)。您可能不需要分组。
Use Northwind
GO
Select ords.OrderID
, ISNULL ( derived1.MyCount , 0) as NoDiscountCount
, ISNULL ( derived2.MyCount , 0) as HasDiscountCount
from dbo.Orders ords
left join
( select innerOd1.OrderID , count (*) as MyCount from dbo.[Order Details] innerOd1 where innerOd1.Discount <=0 group by innerOd1.OrderID) derived1
on ords.OrderID = derived1.OrderID
left join
( select innerOd2.OrderID , count (*) as MyCount from dbo.[Order Details] innerOd2 where innerOd2.Discount > 0 group by innerOd2.OrderID) derived2
on ords.OrderID = derived2.OrderID
order by ords.OrderID
::: APPEND :::
这是第一个。 你可以填写剩下的部分。
declare @theDate datetime
select @theDate = getdate()
select membs.* , currentMemberDerived.[CurrentMember] from
[dbo].[apf_Members] membs
left join
(
Select MemberID , [Description] as 'CurrentMember' from apf_finances
where @theDate between StartDate and EndDate
and Status = 'Financial Status'
) currentMemberDerived
on membs.MemberID = currentMemberDerived.MemberID