Question

我的网站上有一个正在运行的聊天应用程序。它是使用websockets，php实现的，并且工作正常。问题是每当我向单个用户发送消息时，它就会向当前连接到我网站的所有用户广播该消息。如果有人可以告诉我如何在有人连接到我们的应用程序时获得每个用户的唯一ID，这将非常有用。如果我可以获得当前登录的聊天用户的用户ID，这将解决我的问题，但我无法在用户连接时检索该用户ID（打开状态的websocket）。我可以在建立连接时获取用户ID，但在连接发生之前我需要用户ID。当连接发生时，它以连续的方式（1,2,3 ..，n）为连接的用户分配自己的ID。

<?php
// prevent the server from timing out
set_time_limit(0);

// include the web sockets server script (the server is started at the far bottom of this file)
require 'class.PHPWebSocket.php';

// when a client sends data to the server
function wsOnMessage($clientID, $message, $messageLength, $binary) {
global $Server;
$ip = long2ip( $Server->wsClients[$clientID][6] );

// check if message length is 0
if ($messageLength == 0) {
    $Server->wsClose($clientID);
    return;
}

//Send the message to everyone but the person who said it
foreach ( $Server->wsClients as $id => $client )
    if ( $id != $clientID )
        $Server->wsSend($id, "Visitor $clientID ($ip) said "$message"");
}

// when a client connects
function wsOnOpen($clientID)
{
global $Server;
$ip = long2ip( $Server->wsClients[$clientID][6] );

$Server->log( "$ip ($clientID) has connected." );

//Send a join notice to everyone but the person who joined
foreach ( $Server->wsClients as $id => $client )
    if ( $id != $clientID )
        $Server->wsSend($id, "Visitor $clientID ($ip) has joined the room.");
}

// when a client closes or lost connection
function wsOnClose($clientID, $status) {
global $Server;
$ip = long2ip( $Server->wsClients[$clientID][6] );

$Server->log( "$ip ($clientID) has disconnected." );

//Send a user left notice to everyone in the room
foreach ( $Server->wsClients as $id => $client )
    $Server->wsSend($id, "Visitor $clientID ($ip) has left the room.");
}

// start the server
$Server = new PHPWebSocket();
$Server->bind('message', 'wsOnMessage');
$Server->bind('open', 'wsOnOpen');
$Server->bind('close', 'wsOnClose');
// for other computers to connect, you will probably need to change this to your LAN IP or external IP,
// alternatively use: gethostbyaddr(gethostbyname($_SERVER['SERVER_NAME']))
$Server->wsStartServer('127.0.0.1', 9300);

?>

HTML

<!doctype html>
<html>
<head>
<meta charset='UTF-8' />
<style>
    input, textarea {border:1px solid #CCC;margin:0px;padding:0px}

    #body {max-width:800px;margin:auto}
    #log {width:100%;height:400px}
    #message {width:100%;line-height:20px}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="fancywebsocket.js"></script>
<script>
    var Server;

    function log( text ) {
        $log = $('#log');
        //Add text to log
        $log.append(($log.val()?"n":'')+text);
        //Autoscroll
        $log[0].scrollTop = $log[0].scrollHeight - $log[0].clientHeight;
    }

    function send( text ) {
        Server.send( 'message', text );
    }

    $(document).ready(function() {
        log('Connecting...');
        Server = new FancyWebSocket('ws://127.0.0.1:9300');

        $('#message').keypress(function(e) {
            if ( e.keyCode == 13 && this.value ) {
                log( 'You: ' + this.value );
                send( this.value );
                $(this).val('');
            }
        });

        //Let the user know we're connected
        Server.bind('open', function() {
            log( "Connected." );
        });

        //OH NOES! Disconnection occurred.
        Server.bind('close', function( data ) {
            log( "Disconnected." );
        });

        //Log any messages sent from server
        Server.bind('message', function( payload ) {
            log( payload );
        });

        Server.connect();
    });
</script>
</head>

<body>
<div id='body'>
    <textarea id='log' name='log' readonly='readonly'></textarea><br/>
    <input type='text' id='message' name='message' />
</div>
</body>

</html>

Answer 1

在服务器中创建一个temp_users数组。
当每个客户端连接时，创建一个唯一ID并将新套接字和唯一ID添加到此阵列，然后将ID发送到客户端，并带有一个标头，指示这是系统消息。
在客户端代码中，让客户端从系统消息中检索唯一ID。撰写具有唯一ID和客户端用户名的消息，然后将其发送回服务器。
将收到的用户名映射到temp_users数组中的相应ID。您现在可以识别特定用户，并使用映射到其用户名的套接字向他们发送消息。

Websockets与特定用户进行分组聊天

1 个答案: