javax.xml.bind.MarshalException - 链接异常: [javax.xml.stream.XMLStreamException:在其他输出完成后,无法输出XML声明。] at com.sun.xml.bind.v2.runtime.MarshallerImpl.write(MarshallerImpl.java:330) 在com.sun.xml.bind.v2.runtime.MarshallerImpl.marshal(MarshallerImpl.java:178)
这是我的代码段:
OutputStream output = new ByteArrayOutputStream();
XMLOutputFactory xof = XMLOutputFactory.newInstance();
XMLStreamWriter xsw = xof.createXMLStreamWriter(output);
QName root = new QName("return");
JAXBElement<Customer> je = new JAXBElement<Customer>(root, Customer.class, customer);
xsw.writeStartDocument();
xsw.setDefaultNamespace("S");
xsw.writeStartElement("S", "Envelope", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("S", "Body", "http://schemas.xmlsoap.org/soap/envelope/");
xsw.writeStartElement("ns0", "findCustomerResponse", "http://service.jaxws.blog/");
context = JAXBContext.newInstance(Customer.class);
Marshaller marshaller = context.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
marshaller.marshal(je, xsw);
xsw.writeEndDocument();
xsw.close();
if(output != null)
return output.toString();
你有什么想法为什么会这样吗?提前致谢
答案 0 :(得分:0)
您需要在JAXB_FRAGMENT
上指定Marshaller
属性以避免此问题。这个属性让JAXB知道它正在编组到文档的中间,并且它不应该写标题。
了解更多信息