我正在尝试重定向输出,但我有2个问题。问题1:ls -l>文件工作正常,但如果我做cat file1> file2,我的shell似乎在后台无限期地工作。我必须在等待2到3分钟后打断它(Ctrl-D)。 问题2:使用sort<时出现同样的问题水果,我的shell似乎等待一个过程完成,但它永远不会。所以我必须打断它。我知道我做的不对,但我似乎无法弄清楚什么是错的/缺失的。我还没有实现管道。我们将非常感谢您的帮助。
int create_childprocess(char *argv[], int argc)
{
//int pid;
int fd, i, ret;
pid_t pid;
int redirect_sign =0;
if((pid = fork()) == -1)
{
/*error exit -fork failed*/
perror("Fork failed");
exit(-1);
}
if(pid == 0)
{
/*this is the child*/
printf("\nThis is the child ready to execute: %s\n", argv[0]);
for(i=0; i<argc; i++)
{
if((strcmp(">", argv[i])) ==0)
redirect_sign=1;
else if((strcmp(">>", argv[i])) ==0)
redirect_sign=2;
else if((strcmp("<", argv[i])) ==0)
redirect_sign=3;
else if((strcmp("<<", argv[i])) ==0)
redirect_sign=4;
}
if (redirect_sign==1) //if ">" is found...
{
fd = open(argv[argc-1],O_TRUNC | O_WRONLY | O_CREAT, 0755);
if(fd == -1)
{
/*An error occured. Print an error message and bail.*/
perror("open");
exit(-1);
}
else
{
printf("Writing output of the command %s to file created\n", argv[0]);
dup2(fd,1);
execlp(argv[0], argv[0], NULL);
close(fd);
}
}
else if (redirect_sign==2) //if ">>" was found...
{
fd = open(argv[argc-1], O_WRONLY | O_APPEND | O_CREAT, 0755);
if(fd == -1)
{
/*An error occured. Print an error message and bail.*/
perror("open");
exit(-1);
}
else
{
printf("Appending output of the command %s to file created\n", argv[0]);
dup2(fd,1);
execlp(argv[0], argv[0], NULL);
close(fd);
}
}
else if (redirect_sign==3) //if "<" was found...
{
fd = open(argv[argc-1], O_TRUNC | O_WRONLY | O_CREAT, 0755);
if(fd == -1)
{
/*An error occured. Print an error message and bail.*/
perror("open");
exit(-1);
}
else
{
printf("Writing content of file %s to disk\n", argv[argc-1]);
dup2(fd,1);
execlp(argv[0], argv[0], NULL);
close(fd);
}
}
else if (redirect_sign==4) //if "<" was found...
{
fd = open(argv[argc-1], O_TRUNC | O_WRONLY | O_CREAT, 0755);
if(fd == -1)
{
/*An error occured. Print an error message and bail.*/
perror("open");
exit(-1);
}
else
{
printf("Writing content of file %s to %s \n", argv[argc-1], argv[0] );
dup2(fd,1);
execlp(argv[0], argv[0], NULL);
close(fd);
}
}
else //if ">" or ">>" or "<" or "<<" was not found
{
execvp(argv[0], &argv[0]);
/*error exit - exec returned*/
perror("Exec returned");
exit(-1);
}
}
else
{
/*this is the parent -- wait for child to terminate*/
wait(pid,0,0);
printf("\nThe parent is exiting now\n");
}
free (argv);
return 0;
}
答案 0 :(得分:0)
如果不仔细查看代码,可能不会关闭文件描述符。特别是,在调用close(fd)
之前,您肯定希望execlp
,并且要非常小心,您已经关闭了所创建的任何管道中的所有其他相关文件描述符。更正此特定错误并关闭输出文件不太可能解决您的问题;更有可能是你没有显示的代码中有错误,你已经打开了一些管道,以便cat
等待永远不会来的EOF,因为它有管道的写入侧打开,并且该管道的读取端是它自己的标准输入。
答案 1 :(得分:0)
您正在使用dup2(fd,1);在所有情况下。我认为对于input(stdin),你想要替换文件描述符0(或预定义的宏STDIN_FILENO。