我有一个班级:
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Runtime.Serialization", "4.0.0.0")]
[System.Runtime.Serialization.DataContractAttribute(Name="MyClass", Namespace="http://model.common.party.ent.gfdi.be")]
[System.SerializableAttribute()]
public class MyClass : object, System.Runtime.Serialization.IExtensibleDataObject, System.ComponentModel.INotifyPropertyChanged
{
[System.Runtime.Serialization.OptionalFieldAttribute()]
private string firstname;
[System.Runtime.Serialization.OptionalFieldAttribute()]
private string lastname;
}
我创建了一个实例:
var myClass = new MyClass() { lastname = "AAA", firstname = "BBB" };
我想将此实例发送到网络服务。
我想将此对象发送到Web服务。 Web服务收到的消息应如下所示:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:membership="http://service.common.party.ent.gfdi.be
http://service.common.party.ent.gfdi.be">
<soapenv:Header/>
<soapenv:Body>
<membership:find>
<membership:in0>
<membership:lastname>AAA</membership:lastname>
<membership:firstname>BBB</membership:firstname>
</membership:in0>
</membership:find>
</soapenv:Body>
</soapenv:Envelope>
我试过了:
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(myurl);
webRequest.Headers["Authorization"] = "Basic " + "XXXXXXXXXXXXXX=";
webRequest.ContentType = "text/xml; charset=UTF-8";
webRequest.Method = "POST";
XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);
IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);
asyncResult.AsyncWaitHandle.WaitOne();
string soapResult;
using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
{
using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
{
soapResult = rd.ReadToEnd();
}
Console.Write(soapResult);
}
private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
using (Stream stream = webRequest.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
}
private static XmlDocument CreateSoapEnvelope()
{
XmlDocument soapEnvelop = new XmlDocument();
soapEnvelop.LoadXml(@"<SOAP-ENV:Envelope xmlns:SOAP-ENV=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:xsi=""http://www.w3.org/1999/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/1999/XMLSchema""><SOAP-ENV:Body><HelloWorld xmlns=""http://tempuri.org/"" SOAP-ENV:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/""><int1 xsi:type=""xsd:integer"">12</int1><int2 xsi:type=""xsd:integer"">32</int2></HelloWorld></SOAP-ENV:Body></SOAP-ENV:Envelope>");
return soapEnvelop;
}
有什么想法吗?
谢谢,
答案 0 :(得分:0)
阅读你的评论我会做以下事情:
我会请求网络服务网址的用户名/密码,并通过网络浏览器(视觉工作室外)进行身份验证。
然后在项目中,使用添加服务引用 - &gt;高级 - &gt;添加webreference。选项并引入它不应该请求身份验证的URL,因为IExplorer已经过身份验证。
如果您设法获取WSDL服务描述解析并创建WS类,那么您就完成了,因为您可以在使用以下内容时使用Web服务为webService提供基本身份验证:
WebServiceClass wsClass = new WebServiceClass();
wsClass .Credentials = new System.Net.NetworkCredential("user", "password");