如何检查字符串字符是否为空格?

时间:2013-10-20 14:50:56

标签: c# string if-statement

我刚开始用C#编程。我正在尝试构建一个简单的Vigenere文本加密工具作为个人项目。

我的问题应该很容易修复,但它真的强调我找出错误。在我的代码中,我试图做一个简单的检查,看看我的字符串中的字符是否是一个空格;我已经正确设置了我的if语句但它正跳过第一个测试并转移到else,即使第一个测试是真的。我非常喜欢这方面的一些帮助。

我的问题区域在底部。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

public class fun2013
{
public static void Main()
{
    Console.WriteLine("fun 2013");
    string UserName;
    do
    {
        Console.Write("LOGIN//: ");
        UserName = Console.ReadLine();
    }
    while(UserName != "Max");
    Console.WriteLine(("Hello ") + (UserName) + (", enter your key below."));

                //USER ENTERS TEXT AT THIS POINT

    string loweredPass = Console.ReadLine().ToLower();
        Console.WriteLine("Changing CASE...");
        Console.WriteLine(loweredPass);
    string Strippedpass = loweredPass.Replace(" ","");
        Console.WriteLine("STRIPPING SPACES...");
        Console.WriteLine(Strippedpass);
    int passLength = Strippedpass.Length;
        Console.WriteLine("Enter your message below.");
    string userMessage = Console.ReadLine();
    int MessageLength = userMessage.Length;

                //BEGIN PROCESSING STRINGS INTO ARRAYS

    string temp = "";
    StringBuilder bcon = new StringBuilder();
    char [] passArray = Strippedpass.ToCharArray();
    char [] messArray = userMessage.ToCharArray();
    string letterf = "";

    for(int i=0, j=0; j < (MessageLength); i++, j++)    //i used for key array, j used for message length
        {
        >>> if (messArray[i].ToString() == " ")
            {
                letterf = " ";
            }
        else if (messArray[i].ToString() != " ")
            {
                letterf = passArray[i].ToString();
            }
            if (i >= (passLength-1))    //array starts at value 0, length check starts at 1. Subtract 1 to keep them equal
                {i = -1;}   //-1 is used so it will go back to value of 0 on next loop
        temp = letterf;
        bcon.Append(temp);
        }

    Console.WriteLine();
    Console.WriteLine(bcon);


    Console.WriteLine("Press ENTER to continue...");
        Console.ReadLine(); //KILL APPLICATION
}
}

感谢大家的帮助,但经过进一步检查后,我注意到我在for循环中出错了。我使用与键数组(int i)相同的间隔重置消息数组读取器。我改为使用正确的整数“j”。我还将“temp”字符串更新程序和字符串构建器放入循环中的每个if语句中。它现在正常运行。

    for (int i=0, j=0; j < (MessageLength); i++, j++)    //i used for key array, j used for message length
    {

    if (messArray[j].ToString() != " ")
        {
            letterf = passArray[i].ToString();
            temp = letterf;
            bcon.Append(temp);
        }

    else if (messArray[j].ToString() == " ")
        {
            letterf = " ";
            temp = letterf;
            bcon.Append(temp);
        }

    if (i >= (passLength-1))    //array starts at value 0, length check starts at 1. Subtract 1 to keep them equal
        {i = -1;}   //-1 is used so it will go back to value of 0 on next loop
    }

5 个答案:

答案 0 :(得分:6)

Char.IsWhiteSpace(char)

另请参阅String.IsNullOrEmptyString.IsNullOrWhiteSpace

答案 1 :(得分:0)

  

我正在尝试做一个简单的检查,看看我的字符串中的字符是否是空格;

您可以更改此代码

messArray[i].ToString() != " "

char.IsWhiteSpace(messArray[i])

答案 2 :(得分:0)

尝试

Char.IsWhiteSpace(角色)

来自msdn的示例:

public class IsWhiteSpaceSample {
public static void Main() {
    string str = "black matter"; 

    Console.WriteLine(Char.IsWhiteSpace('A'));      // Output: "False"
    Console.WriteLine(Char.IsWhiteSpace(str, 5));   // Output: "True"
}
}

答案 3 :(得分:0)

您似乎错过了密码的基本部分,即根据关键字母抵消消息字母的数量。此外,您将要忽略任何无法加密到字母的字符:“:”,“!”,“,”等等,而不仅仅是空格。

扰流警报

using System;
using System.Text;
using System.Text.RegularExpressions;

public class fun2013
{
    public static void Main()
    {
        Console.WriteLine("fun 2013");
        string userName = "";
        do
        {
            Console.Write("LOGIN//: ");
            userName = Console.ReadLine();
        }
        while (userName != "Max");
        Console.Write("Hello " + userName + ", enter your key: ");

        // Get a user-input key and make sure it has at least one usable character.
        // Allow only characters [A-Za-z].
        string viginereKey;
        do
        {
            viginereKey = Console.ReadLine();
            // remove everything which is not acceptable
            viginereKey = Regex.Replace(viginereKey, "[^A-Za-z]", "");
            if (viginereKey.Length == 0)
            {
                Console.Write("Please enter some letters (A-Z) for the key: ");
            }
        }
        while (viginereKey.Length == 0);

        // no need to create a new variable for the lowercase string
        viginereKey = viginereKey.ToLower();
        // "\n" in a string writes a new line
        Console.WriteLine("Changing CASE...\n" + viginereKey);

        int keyLength = viginereKey.Length;

        Console.WriteLine("Enter your message:");
        string message = Console.ReadLine();
        message = message.ToLower();
        int messageLength = message.Length;

        StringBuilder cipherText = new StringBuilder();

        // first and last characters to encipher
        const int firstChar = (int)'a';
        const int lastChar = (int)'z';
        const int alphabetLength = lastChar - firstChar + 1;

        int keyIndex = 0;

        for (int i = 0; i < messageLength; i++)
        {
            int thisChar = (int)message[i];

            // only encipher the character if it is in the acceptable range
            if (thisChar >= firstChar && thisChar <= lastChar)
            {
                int offset = (int)viginereKey[keyIndex] - firstChar;
                char newChar = (char)(((thisChar - firstChar + offset) % alphabetLength) + firstChar);
                cipherText.Append(newChar);

                // increment the keyIndex, modulo the length of the key
                keyIndex = (keyIndex + 1) % keyLength;
            }
        }

        Console.WriteLine();
        Console.WriteLine(cipherText);

        Console.WriteLine("Press ENTER to continue...");
        Console.ReadLine(); // Exit program
    }
}

答案 4 :(得分:0)

您应该能够做到这一点:

if (messArray[i] == ' ') // to check if the char is a single space