Question

我的代码如下

static void Main(string[] args)
    {
        string startPath = @"c:\Temp\att\";
        string xmlpath = @"c:\Temp\log\";
        var files = Directory.GetFiles(xmlpath, "*.*", SearchOption.AllDirectories)
        .Where(s => s.EndsWith(".xml"));

        foreach (string xml in files)
        {
            XmlDocument doc = new XmlDocument();
            doc.Load(xml);
            XmlNodeList Xe = doc.SelectNodes("//FileDump/Message/Attachment");
            var Message_ID = doc.SelectSingleNode("//FileDump/Message/MsgID").InnerXml;
            foreach (XmlNode Xn in Xe)
            {
                var linkNode = Xn.SelectSingleNode("FileName");
                if (linkNode != null)
                {
                    string link = linkNode.InnerText.Trim();
                }
                string File_Name = Xn.SelectSingleNode("FileName").InnerXml;
                string File_ID = Xn.SelectSingleNode("FileID").InnerXml;


                //System.IO.File.Copy(curFile, msgsave, true);

                string msgsave = @"c:\Temp\ZIP\" + File_Name;
                string curFile = startPath + File_Name;
                string bbgfile = xmlpath + "MR_" + Message_ID + ".xml";
                string zipfilename = "MR_" + Message_ID + ".zip";
                string rkzip = System.IO.Path.Combine(@"C:\Temp\log\", zipfilename);

                try
                {

                    using (ZipFile zip = new ZipFile())
                    {
                        string zipFileName = System.IO.Path.Combine(@"C:\Temp\log\",  "MR_" + Message_ID + ".zip");
                        zip.AddFile(curFile, "");
                        zip.AddFile(bbgfile, "");
                        zip.Save(rkzip);
                    }

                }

问题如下： FileName有多个文件，它只会拉链一个文件，我尝试调试我的代码，它显示3个文件，但只有一个文件是压缩的。谁可以概述我的代码有什么问题？ FileName是xml文件中附件文件的指示器

Answer 1

是的，您只会看到写入最后一行，因为您正在创建一个新的zip文件并覆盖以前的时间。您需要将zip文件的创建和保存移至foreach (XmlNode Xn in Xe)之外，或使用ZipFile.Open打开现有的zip文件并进行更新。

Answer 2

class Program
{
    static void Main(string[] args)
    {
        string startPath = @"c:\Temp\att\";
        string xmlpath = @"c:\Temp\log\";
        var files = Directory.GetFiles(xmlpath, "*.*", SearchOption.AllDirectories)
        .Where(s => s.EndsWith(".xml"));

        foreach (string xml in files)
        {
            XmlDocument doc = new XmlDocument();
            doc.Load(xml);
            XmlNodeList Xe = doc.SelectNodes("//FileDump/Message/Attachment");
            var Message_ID = doc.SelectSingleNode("//FileDump/Message/MsgID").InnerXml;
            foreach (XmlNode Xn in Xe)
            {
                var linkNode = Xn.SelectSingleNode("FileName");
                if (linkNode != null)
                {
                    string link = linkNode.InnerText.Trim();
                }
                string File_Name = Xn.SelectSingleNode("FileName").InnerXml;
                string File_ID = Xn.SelectSingleNode("FileID").InnerXml;

                //System.IO.File.Copy(curFile, msgsave, true);

            }
            try
            {
                string msgsave = @"c:\Temp\ZIP\" + doc.SelectSingleNode("//FileDump/Message/Attachment/FileName").InnerXml;
                string curFile = startPath + doc.SelectSingleNode("//FileDump/Message/Attachment/FileName").InnerXml;
                string bbgfile = xmlpath + "MR_" + Message_ID + ".xml";
                string zipfilename = "MR_" + Message_ID + ".zip";
                string rkzip = System.IO.Path.Combine(@"C:\Temp\log\", zipfilename);

                using (ZipFile zip = new ZipFile())
                {
                    string zipFileName = System.IO.Path.Combine(@"C:\Temp\log\", "MR_" + Message_ID + ".zip");
                    zip.AddFile(curFile, "");
                    zip.AddFile(bbgfile, "");
                    zip.Save(rkzip);
                }

            }

即使我在foreach循环外面使用了zip，它仍然只会压缩第一个FileName，即使有3个File_Name

搜索字符串未正确传递

2 个答案: