我的代码应该在j列中查找一些值,如果找到它们,则删除第1列到第11列之间的行。但是,我总是得到错误“无法获取范围的findnext属性class“associated to”Set c = .FindNext(c)“。有什么问题?感谢!!!
Sub ExcluirGraosIncompletos()
Application.ScreenUpdating = False
Dim c As Range
Dim ClearAddress As String
Dim ClearRow As Long
With Worksheets("ListBCOGJ").Range("J4:J17780")
Set c = .Find(What:=6, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=5, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=42, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=66, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=36, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=1, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=4, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=2, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=27, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
Set c = .Find(What:=60, LookIn:=xlValues, LookAt:=xlWhole, _
MatchCase:=True)
If Not c Is Nothing Then
ClearAddress = c.Address
Do
ClearRow = c.Row
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp
Set c = .FindNext(c)
Loop While c.Address <> ClearAddress
End If
End With
Application.CutCopyMode = False
Range("A1").Select
Application.ScreenUpdating = True
End Sub
答案 0 :(得分:1)
这是因为您要删除Find
引用的范围。
将FindNext
向上移动一行以便在删除行之前更新它应该可以正常工作,如下所示:
ClearRow = c.Row
Set c = .FindNext(c)
Range(Cells(ClearRow, 1), Cells(ClearRow, 11)).Delete Shift:=xlUp