Question

我有一个对象的文本文件，我正在从中提取信息，数据存储如下：

name。| description | 2013-10-19 23:25:58 +0000 | NO | NO

name。| description | 2013-10-19 23:25:58 +0000 | NO | NO

name。| description | 2013-10-19 23:25:58 +0000 | NO | NO

要将每一行放入一个字符串数组中，我会执行以下操作：

NSArray *objectArray = [saveData componentsSeparatedByString:@"\n"];

将生成一个包含各个字符串的数组：

name。| description | 2013-10-19 23:25:58 +0000 | NO | NO

然后我想要额外添加每个字符串的每个字段。

 NSMutableArray *items = [[NSMutableArray alloc] init];
    for (NSString *string in objectArray) {
        [items removeAllObjects];
        [items addObject:[string componentsSeparatedByString:@"|"]];
        for (int i = 0; i < [items count]; i++) {
            NSLog(@"%d      %@", i, [items objectAtIndex:i]);
        }
    }

但这只是产生整条线而不是单个字段？

编辑：我的问题是我的原始saveData字符串。让我没先验证它是正确的！

上面的代码工作正常，并产生如下输出：

2013-10-20 11:15:11.152 Wakely[3571:11603] 0      (
"name.1",
"desc",
"2013-10-20 00:15:05 +0000",
NO,
NO
)
2013-10-20 11:15:11.155 Wakely[3571:11603] 0      (
"name.2",
"desc",
"2013-10-20 00:15:07 +0000",
NO,
NO

）

我不应该使用[items objectAtIndex：0]来获取name1吗？它似乎已被存储为一个整体，单个对象与行描述而不是5个分隔的字符串？

Answer 1

NSString* test = @"name.|description|2013-10-19 23:25:58 +0000|NO|NO";

NSArray* testarray = @[test,test,test];

NSMutableArray* finalArray = [[NSMutableArray alloc]init];

for (NSString* teststring in testarray) {
    [finalArray addObject:[teststring componentsSeparatedByString:@"|"]];
}

NSLog(@"%@",finalArray);

结果：

2013-10-20 01:46:47.484 test[38523:60b] (
        (
        "name.",
        description,
        "2013-10-19 23:25:58 +0000",
        NO,
        NO
    ),
        (
        "name.",
        description,
        "2013-10-19 23:25:58 +0000",
        NO,
        NO
    ),
        (
        "name.",
        description,
        "2013-10-19 23:25:58 +0000",
        NO,
        NO
    )
)

用你的东西编辑：

NSArray *objectArray = [saveData componentsSeparatedByString:@"\n"];

NSMutableArray* finalArray = [[NSMutableArray alloc]init];

for (NSString* teststring in objectArray) {
    [finalArray addObject:[teststring componentsSeparatedByString:@"|"]];
}

NSLog(@"%@",finalArray);

编辑2：

NSArray* firstItem = finalArray[0];
NSString* name1 = firstItem[0];

Answer 2

与incmiko的做法类似，但使用块而不是for循环。

    NSString* test = @"name.|description|2013-10-19 23:25:58 +0000|NO|NO";

    NSArray *multipleLines = @[test, test, test];

    [multipleLines enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
        NSLog(@"%@", [obj componentsSeparatedByString:@"|"]);
    }];

输出：

2013-10-19 19:48:58.522 Strings[407:303] (
    "name.",
    description,
    "2013-10-19 23:25:58 +0000",
    NO,
    NO
)
2013-10-19 19:48:58.523 Strings[407:303] (
    "name.",
    description,
    "2013-10-19 23:25:58 +0000",
    NO,
    NO
)
2013-10-19 19:48:58.524 Strings[407:303] (
    "name.",
    description,
    "2013-10-19 23:25:58 +0000",
    NO,
    NO
)

Answer 3

这是因为您在items数组中添加了NSArray作为整个对象。尝试使用代码，它应该打印单个项目，而不是整个数组：

NSString* test = @"name.|description|2013-10-19 23:25:58 +0000|NO|NO";
NSString* test1 = @"name1.|description1|2013-10-19 23:25:58 +0001|NO1|NO1";

NSArray *objectArray = @[test,test1];

NSMutableArray *items = [NSMutableArray array];

for (NSString *string in objectArray) {
    [items addObjectsFromArray:[string componentsSeparatedByString:@"|"]];
}

NSLog(@"First Item = %@", items[0]);

多次拆分NSStrings

3 个答案: