我正在练习python的euler问题，我似乎无法为problem 17得到正确的答案。问题是找到所有数字1-1000的字母数，没有空格或连字符。 任何评论都会有用。
Python代码：
def numberToString(number):
""" Writes a cardinal number to a string. """
numberString=""
c = str(number)
l = len(c)
while l>0:
if l == 1: #unit digit
if int(c[-1]) == 1:
numberString += 'one'
elif int(c[-1]) == 2:
numberString += 'two'
elif int(c[-1]) == 3:
numberString += 'three'
elif int(c[-1]) == 4:
numberString += 'four'
elif int(c[-1]) == 5:
numberString += 'five'
elif int(c[-1]) == 6:
numberString += 'six'
elif int(c[-1]) == 7:
numberString += 'seven'
elif int(c[-1]) == 8:
numberString += 'eight'
elif int(c[-1]) == 9:
numberString += 'nine'
l = l-1
elif l == 2 and int(c[-2])==1 and int(c[-1]) != 0: #teens
if int(c[-1]) == 1:
numberString += 'eleven'
elif int(c[-1]) == 2:
numberString += 'twelve'
elif int(c[-1]) == 3:
numberString += 'thirteen'
elif int(c[-1]) == 4:
numberString += 'fourteen'
elif int(c[-1]) == 5:
numberString += 'fifteen'
elif int(c[-1]) == 6:
numberString += 'sixteen'
elif int(c[-1]) == 7:
numberString += 'seventeen'
elif int(c[-1]) == 8:
numberString += 'eighteen'
elif int(c[-1]) == 9:
numberString += 'nineteen'
l = l-2
elif l == 2: #tens
if int(c[-2]) == 1:
numberString += 'ten'
elif int(c[-2]) == 2:
numberString += 'twenty'
elif int(c[-2]) == 3:
numberString += 'thirty'
elif int(c[-2]) == 4:
numberString += 'fourty'
elif int(c[-2]) == 5:
numberString += 'fifty'
elif int(c[-2]) == 6:
numberString += 'sixty'
elif int(c[-2]) == 7:
numberString += 'seventy'
elif int(c[-2]) == 8:
numberString += 'eighty'
elif int(c[-2]) == 9:
numberString += 'ninety'
if int(c[-1]) != 0 and int(c[-2]) > 1:
numberString += '-'
l = l-1
elif l == 3: #hundreds
if int(c[-3]) == 1:
numberString += 'one'
elif int(c[-3]) == 2:
numberString += 'two'
elif int(c[-3]) == 3:
numberString += 'three'
elif int(c[-3]) == 4:
numberString += 'four'
elif int(c[-3]) == 5:
numberString += 'five'
elif int(c[-3]) == 6:
numberString += 'six'
elif int(c[-3]) == 7:
numberString += 'seven'
elif int(c[-3]) == 8:
numberString += 'eight'
elif int(c[-3]) == 9:
numberString += 'nine'
if int(c[-3]) != 0:
numberString += ' hundred'
if int(c[-1])+int(c[-2]) != 0:
numberString += ' and '
l = l-1
elif l == 4: #thousands
if int(c[-4]) == 1:
numberString += 'one'
elif int(c[-4]) == 2:
numberString += 'two'
elif int(c[-4]) == 3:
numberString += 'three'
elif int(c[-4]) == 4:
numberString += 'four'
elif int(c[-4]) == 5:
numberString += 'five'
elif int(c[-4]) == 6:
numberString += 'six'
elif int(c[-4]) == 7:
numberString += 'seven'
elif int(c[-4]) == 8:
numberString += 'eight'
elif int(c[-4]) == 9:
numberString += 'nine'
if int(c[-4]) != 0:
numberString += ' thousand'
if int(c[-3]) != 0:
numberString += ' '
l = l-1
return numberString
def NumbersInString(min, max):
""" Writes all cardinal numbers on a seperate line on a string, from min to max. """
allNumberString=""
for i in range (min,max+1):
allNumberString += numberToString(i)
allNumberString += '\n'
return allNumberString
def stringNumberCount(numberString):
""" Returns the ammount of letters without spaces, hyphens or newlines. """
numberString=numberString.replace(' ', '')
numberString=numberString.replace('-', '')
numberString=numberString.replace('\n', '')
return len(numberString)
def run(filename, min=1, max=1000):
s=NumbersInString(min, max)
string='Number of letters without spaces or hyphens: '+str(stringNumberCount(s))+'\n'+'List of cardinal numbers:\n'
string += s
f=open(filename, 'w')
f.write(string)
f.close
run('output.txt')
答案 0 :(得分：0)
首先你将四十岁改为四十岁（如问题陈述所述）
和第二 在elif l == 3：块 为什么你写作如果int（c [-3]！= 0）： 因为我们之前就已经涵盖了这些情况（我的意思是c [-3] == 1,2,3 ......不等于零） 如果我错了，请纠正我，并尝试在您的代码中添加一些注释。
def countLetter(n):
p=['','One','Two','Three','Four','Five','Six','Seven','Eight','Nine']
q=['','Ten','Twenty','Thirty','Forty','Fifty','Sixty','Seventy','Eighty','Ninety']
r=['','Eleven','Twelve','Thirteen','Fourteen','Fifteen','Sixteen','Seventeen','Eighteen','Nineteen']
c=str(n)
l=len(c)
a=""
if l==1:
a+=p[int(c[0])]
elif l==2:
if c[1]=='0':
a+=q[int(c[0])]
elif c[0]=='1':
a+=r[int(c[1])]
else:
a+=q[int(c[0])]+p[int(c[1])]
elif n==100:
a+="OneHundred"
elif l==3:
a+=p[int(c[0])]+"Hundred"
if c[1]=='0' and c[2]=='0':
a+=""
elif c[2]=='0' and c[1]!='0':
a+="And"+q[int(c[1])]
elif c[1]=='1':
a+="And"+r[int(c[2])]
else:
a+="And"+q[int(c[1])]+p[int(c[2])]
else:
a+="OneThousand"
#print a,len(a)
return len(a)
def main():
sum=0
for i in range(1,1001):
sum+=countLetter(i)
print sum
main()