Java缓冲区读取器在ctrl z上崩溃

时间:2013-10-19 14:59:56

标签: java

嗨我正在玩游戏,直到用户在命令行中退出。

用户可以输入不同的命令,比如get and go,使用get命令,用户可以说出了什么,得到棒球棒。我在我的代码中做的是拆分命令。 一切正常,但我发现了一个我无法解决的错误。如果我输入get并按 space 然后 ctrl z 它会进入一个永远不会结束的while循环。 它只发生在 ctrl z (1次用 ctrl c 但在那之后不再有了1次)

我知道它的代码很重要,但我非常感谢任何帮助 我的代码

 private void run() 
{       
    while (! quitCommand)
    {

        String input = null;

        try 
        {   
            input = null;
            System.out.println("Input "+ input);
            System.out.println("Give a command.");
            BufferedReader is = new BufferedReader(new InputStreamReader(System.in));
            input = is.readLine();
            handleCommand(input);
            // As long as the command isn’t to quit:
            // get the next input line and handle it. (With handleCommand.)
        } 

        catch (Exception e) 
        {
            System.out.println("Something went wrong we are sorry try again.");
            e.printStackTrace();
        }

    }
}

/**
* @param userInput (This is the entire input string from the user.)
*
* (Tell others to) Perform the task which belongs to the given
* command.
*/
private void handleCommand(String userInput) 
{


    // Split the user input string.
    if (userInput != null)          // user input can not be empty
    {
        String[] delenTekst = userInput.split(" ");

        // The first word is a command. The rest is extra information
        String command = delenTekst[0];
        String extra = "";

        for (int i = 1; i < delenTekst.length; i ++)
        {
            if (i == 1)
            {
                extra = extra + delenTekst[i];
            }
            else
            {
                extra = extra +" " + delenTekst[i];
            }

        }


        switch (command)
        {
            // Check if the command is to travel between rooms. If so, handle


            case "go"
            : 

                this.checkRoomTravel(extra);
                break;

            // If there isn’t any room travel, then check all other command


            case "get"
            :   
                System.out.println("Looking for " +extra );
                this.handleGetCommand(extra);
                break;

            case "quit"
            :
                quitCommand = true;
                break;

            default
            :
                System.out.println("Command is not known try help for information");
                break;  
        }
    }
    else
    {
        userInput = "help";
    }
}

我是java的新手,所以它可以是非常简单的东西。

在我的脚本顶部我有一个私有布尔quitCommand = false;这是检查用户是否输入了退出

2 个答案:

答案 0 :(得分:1)

Ctrl + Z 关闭控制台,因此您的readLine()返回null,假装表示已到达文件末尾。因此,您需要做的就是检查null返回的readLine(),并在处理“退出”时处理此问题。

我已经改变了你的代码(只是为了测试我的论文)并且还提供了一些内容,例如:每次读一行时都不需要重新创建BufferedReader

private boolean quitCommand = false;
 private void runIt() {       
     BufferedReader is = new BufferedReader(new InputStreamReader(System.in));
     String input = null;

     while(!quitCommand) {
         try {   
             System.out.print("Give a command: ");
             input = is.readLine();

             // As long as the command isn’t to quit:
             if(input == null || "quit".equals(input.trim())) quitCommand = true;
             if(quitCommand) break;

             // get the next input line and handle it. (With handleCommand.)
             String[] words = input.trim().split("\\s+");

             // ** This is the original handleCommand line **
             System.out.println(input + ":" + Arrays.toString(words));
         } 
         catch (Exception e) {
             System.out.println("Something went wrong we are sorry try again.");
             e.printStackTrace();
         }
     }
 }

顺便说一句:要将输入分成单词,我会使用正则表达式,如我的代码所示。如果用户输入制表符或多个空格,这也适用。

答案 1 :(得分:0)

在DOS / Windows Ctrl + Z 表示输入结束。这会导致readLine()返回null,无论您调用它多少次。这可能会导致您的代码失败,因为您似乎没有检查它。我怀疑你得到一个NullPointerException,你假装没有发生,并且无休止地再次尝试。