Question

请帮助我，这是我的代码。在启动之前它不会显示任何错误。但当我运行应用程序它不显示任何数据。当我检查数据库文件时，没有表创建小心帮助我

谢谢＆amp;问候 Gurmeet Singh

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    SQLiteDatabase myDB= null;
    String TableName = "Dictionary";
    String Data="";
    try {
           myDB = this.openOrCreateDatabase("Punjabishabdkosh", MODE_PRIVATE, null);

           myDB.execSQL("CREATE TABLE IF NOT EXISTS "
                     + TableName
                     + " (Field1 VARCHAR, Field2 VARCHAR);");

           myDB.execSQL("INSERT INTO "
                     + TableName
                     + " (Field1, Field2)"
                     + " VALUES ('Gurmeet', Tiwana);");


           Cursor c = myDB.rawQuery("SELECT * FROM " + TableName , null);

           int Column1 = c.getColumnIndex("Field1");
           int Column2 = c.getColumnIndex("Field2");

           c.moveToFirst();
           if (c != null) {

              do {
                String Name = c.getString(Column1);
                int Age = c.getInt(Column2);
                Data =Data +Name+"/"+Age+"\n";
              }while(c.moveToNext());
           }
           TextView tv = new TextView(this);
           tv.setText(Data);
           setContentView(tv);

    } catch(Exception e) {
        Log.e("Error", "Error", e);
    } finally {
        if (myDB != null)
           myDB.close();
        }
    }
}

Answer 1

以下语句包含错误：

myDB.execSQL("INSERT INTO "
                 + TableName
                 + " (Field1, Field2)"
                 + " VALUES ('Gurmeet', Tiwana);");

由于Field1和Field2都是VARCHAR字段，“Tiwana”一词需要用单引号括起来，所以我认为插入失败了，这就是为什么你不要看到任何数据。将语句更改为：

myDB.execSQL("INSERT INTO "
                 + TableName
                 + " (Field1, Field2)"
                 + " VALUES ('Gurmeet', 'Tiwana');");

数据库无法正常工作

1 个答案: