Question

我在字符指针中有日期时间 -

char *connectTime = "2013-10-19 01:10:00";

然后我获取当前时间，这将是断开时间。

time_t disconnectTime;
disconnectTime = time(NULL);

现在，我想从disconnectTime中减去connectTime。我用Google搜索但无法实现它。请帮忙。

Answer 1

您可以使用strptime()将connectTime转换为struct tm，然后对后者使用mktime()将其转换为time_t。

char * connectTime = "2013-10-19 01:10:00";
struct tm tmConnect = {0};
time_t timeConnect;
char * pc = strptime(connectTime, "%Y-%m-%d %H:%M:%S", &tmConnect);
if ((NULL == pc) || ('\0' != *(pc + strlen(connectTime))) /* The second condition assume connectTime does not hold any more characters after "... 01:10:00". */
{
  perror("strptime() failed");
  /* handle error */
}
else
{
  timeConnect = mktime(&tmConnect);
}

然后计算使用difftime()的秒数差异，如 Grijesh Chauhan 的评论所述：

time_t disconnectTime;
disconnectTime = time(NULL);
double diff = difftime(disconnectTime, timeConnect);

从time_t中减去char指针

1 个答案: