Question

好的，所以我正在进行基于文本的冒险，并且我引入了变量gold。我试图在其中一个故事选项中做到这一点，你可以选择拿起黄金。我的语法如下：

if choice == "A":
    print("There is no answer. But there is 5 gold on the floor, would you like to pick it up? Type: YES or NO")
yesorno = input()
if yesorno == "YES":
    g = g + 5
    print("You picked them up.",ge,"g")


elif choice == "B":
    print("Someone from a long distance away shouts: 'Shut up",name,"!'. Then the man walks away down what seems like a echoey corridor.")

elif choice == "C":
    print("Nothing happens, you are left to die.")
    sys.exit("You lost")

选择'A'可以正常工作，但如果我想选择B或C，我必须输入两次，如下所示：

Either type A, B or C to choose.
B
B
Someone from a long distance away shouts: 'Shut up g !'. Then the man walks away down     what seems like a echoey corridor.

Answer 1

假设您使用的是python 3，我认为问题在于缩进和未定义的变量ge

if choice == "A":
    print("There is no answer. But there is 5 gold on the floor, would you like to pick it up? Type: YES or NO")
    yesorno = input()
    if yesorno == "YES":
        g = g + 5
        print("You picked them up.",g,"g")
elif choice == "B":
    print("Someone from a long distance away shouts: 'Shut up",name,"!'. Then the man walks away down what seems like a echoey corridor.")
elif choice == "C":
    print("Nothing happens, you are left to die.")
    sys.exit("You lost")

嵌套的if语句不起作用

1 个答案: