KnockoutJs从Json webservice更新视图模型单个observable

Question

淘汰新手，Js的新人，我是一个点网开发者，试图创建一个淘汰登录屏幕，发布数据很好，接收响应OK，只是无法弄清楚如何更新单个observable，请帮忙。 ..

function AppViewModel() {
this.email = ko.observable("Bergmail.com");
this.password = ko.observable("Password");
this.logonresult = ko.observable("logon resul");
//computed
this.Computedresult = ko.computed(function () {
    return this.email() + " " + this.password();
}, this);
    //behavious
this.Loginajax = function () {

    var self=this
    $.ajax("Indi-Dal-Json.asmx/CheckLogon" ,{
        data: ko.toJSON({ email: this.email,password: this.password}),
        type: "post", contentType: "application/json",
        success: function (ajaxjsondata) {
            {
                // var parsedjson = JSON.parse(result.b);
                //AppViewModel.logonresult = (result.d);
                self.logonresult = ajaxjsondata.d;
            }

        }
    });
   };
 }

Answer 1

self.logonresult是一个可观察的，所以你需要调用它，而不是用新值覆盖它的引用。

更改

self.logonresult = ajaxjsondata.d;

到

self.logonresult(ajaxjsondata.d);

http://knockoutjs.com/documentation/observables.html#reading_and_writing_observables

Answer 2

Anders回答

self.logonresult(ajaxjsondata.d);

http://knockoutjs.com/documentation/observables.html#reading_and_writing_observables