Question

所以，我一直在制作基于文本的冒险游戏，它会询问你的年龄。如果你的年龄小于13岁则退出游戏，如果它更大或相等也可以让你玩。我现在要做的就是这样做，如果年龄不是一个数字，它会要求你租用年龄，所以有点重播剧本。

有没有办法做到这一点？

age = input()

if age >= 13:
print("You are old enough to play! Let's get started!")

elif age != int:
print("This is not a number")

（该语法不起作用，加上我希望它再次让您输入年龄进行验证。）

else:
    print("You are not old enough.")
    time.sleep(1)
    sys.exit("Please exit the console, you are too young to play.")

Answer 1

while True:
    age = raw_input("Please enter your age > ")
    try:
        age = int(age)
    except ValueError:
        print "Please enter a number"
        continue
    else: 
        break

print "You age is {0}".format(age)

# Now do whatever you want with `age`
if age < 13:
    print "You are not old enough to play the game!"
    sys.exit(1)

这会反复询问你的年龄，直到你最后给它一个数字，此时它会突破循环。

Answer 2

尝试以下代码

import sys
while True:
    age = raw_input("Please enter your age > ")
    try:
        age = int(age)
    except ValueError:
        print "This is not a number"
    else:
        if age >= 13:
            print("You are old enough to play! Let's get started!")
            break
        else:
            print("You are not old enough.")
            sys.exit("Exiting the console, you are too young to play.")

Answer 3

尝试：

#!/usr/bin/env python
import sys
try:
    age = int(input("How old are you?"))
except ValueError:
    print "Enter a valid number. (integer)."
else:
    if age >= 13: # if age is more than 12
        #run program
        print "Game starting!" # code for game loop would start here
    else:
        print "You are too young!" # if less than 13 is entered, this is run
        sys.exit("You must be 13 or above to play this game")

如果它不等于数字，请再次询问年龄

3 个答案: