所以这是我的main()
的代码int main(int argc, char **argv) {
if (argc != 3) {
puts("Invalid number of args in the input. Sorry.");
return 0;
}
if (doesItExist(argv[2]) == 0) {
return 0;
}
FILE *fpoint;
char yesorno[2];
tail = (WordN) malloc(sizeof(struct WordNode));
tail->word = "";
tail->first = (FileN) malloc(sizeof(struct FileNode));
(tail->first)->freq = -1;
ftw(argv[2], tokeForMe, 1);
/**
fpoint = fopen(argv[1], "r");
if(fpoint != NULL) { // file exists give user option to overwrite or rename
getInput("Do you want to overwrite the file? Enter only either Y or N nothing else\n", yesorno, 2);
if(yesorno[0] == 'N' || yesorno[0] == 'n') {
puts("All right. Not going to proceed with the program");
return 0;
}
else if(yesorno[0] != 'Y' && yesorno[0] != 'y') {
puts("You inputted some other character, try again \n");
getInput("Do you want to overwrite the file? Enter Y or N. Do not enter anything other than 1 Y or 1 N \n", yesorno, 2);
}
}
fclose(fpoint);
**/
FILE *index;
index = fopen(argv[1], "w");
//puts("here");
writeToIndex(index, tail->next); //tail is pointing to the first word node
puts("there");
if (doesItExist(argv[1]) == 0) {
return 0;
}
fclose(index);
TailTerminate();
return 0;
}
当我创建一个读取argv [1]的文件指针以确定用户是否想要覆盖argv [1]中指定的文件时,当我取消注释该部件时,代码段出现故障。
程序本身只是一个程序,它从文件目录中创建一种索引器,然后将其打印出来。目录路径在argv [2]中指定,打印索引的路径在argv [1]中指定。
有人可以帮我吗?程序的其余部分(Tail节点等)只是列出程序中出现的单词和频率。
答案 0 :(得分:2)
您没有显示从main
(getInput
?)调用的所有函数,并且它们可能包含错误。从你的注释代码中,我只能说你写了这样的东西:
FILE *f = fopen(...);
if (f != NULL)
{
/* use f */
}
fclose(f);
但它应该是这样的:
FILE *f = fopen(...);
if (f != NULL)
{
/* use f */
fclose(f);
}
也就是说,不要使用fclose()
指针调用NULL
。