Question

我正在处理这个程序，在这里我试图将字符串电子邮件分开，按照＆＃39;，然后我将其存储在数组中，然后附加＆＃39; city＆＃39;在foreach ..

$email='aa,bb,cc,dd';
$a=explode(',',$email);
//echo $a[2];
$result="";
foreach($a as $v)
{
     $result .= " city = '$v' ";
     echo $result;
}

我的结果是

city = 'aa' city = 'aa' city = 'bb' city = 'aa' city = 'bb' city = 'cc' city = 'aa' city = 'bb' city = 'cc' city = 'dd'

但我希望它是，

city = 'aa' city = 'bb' city = 'cc' city = 'dd'

我的代码错了吗？..请指导我..

Answer 1

将echo移出循环，因为你在循环中构建整个字符串，这将每次都回显字符串。

$result="";
foreach($a as $v)
{
     $result .= " city = '$v' ";

}

     echo $result;  // move it here

Answer 2

您根据自己的代码获得了结果，echo执行每个loop的结果。

因此，要在$ result中获取最终值，echo在loop之外。

foreach($a as $v)
{
    $result .= " city = '$v' ";
}
echo $result;

Answer 3

删除结果中的字符串连接

 $email='aa,bb,cc,dd';
$a=explode(',',$email);
//echo $a[2];
$result="";
foreach($a as $v)
{
     $result = " city = '$v' ";//changed $result .= " city = '$v' "; to $result = " city = '$v' ";
     echo $result;
}

Answer 4

你在foreach中回显$ result，所以你的字符串或变量是重复的。请尝试以下代码：

$email='aa,bb,cc,dd';
$a=explode(',',$email);

$result="";
foreach($a as $v)
{
    $result .= " city = '$v' ";     
}
echo $result;

Answer 5

删除字符串concat ..

$email='aa,bb,cc,dd';
$a=explode(',',$email);
//echo $a[2];
$result="";
foreach($a as $v)
{
     $result = " city = '$v' ";  // remove string concate..
     echo $result;
}

另一种方法是在foreach循环之外的回声 ......

$email='aa,bb,cc,dd';
$a=explode(',',$email);
//echo $a[2];
$result="";
foreach($a as $v)
{
     $result .= " city = '$v' "; 
}

echo $result; // echo outside the foreach loop

的输出

city = 'aa' city = 'bb' city = 'cc' city = 'dd'

在PHP中爆炸到数组

5 个答案: