Question

我正在学习flickr api的过程中，在项目中使用它时出现了问题......我有flickr检索照片数据的地方（如下所示）

enter image description here

但它不显示图像本身...我认为这是因为它没有构建<img />标签，下面有src=" "信息是我的代码试图使用......

（我的class.flickr.php代码文件）

class Flickr{

    private $flickr_key;
    private $flickr_secret;
    private $format = 'json';

    // Setting up flickr_key and flickr_secret
    public function __construct( $flickr_key ) {

        $this->flickr_key = $flickr_key;
    }

    public function searchPhotos( $query = '', $tags = '' ){ // Begin searchPhotos 

        $urlencoded_tags = array( 'animals', 'design', 'phones');

        if ( !empty( $args )) {

            $tags_r = explode( ',', $tags );
            foreach ( $tags_r as $tag ) {

                $urlencoded_tags[] = urlencode( $tag );
            }
        }

        // Construct the url
        $url  = 'http://api.flickr.com/services/rest/?';
        $url .= 'method=flickr.photos.search';
        $url .= '&text=' . urlencode( $query );
        $url .= '&tags=' . implode( ',', $urlencoded_tags );
        $url .= '&sort=relevance';
        $url .= '&safe_search=1';
        $url .= '&content_type=4';
        $url .= '&api_key=' . $this->flickr_key;
        $url .= '&format' . $this->format;
        $url .= '&per_page=10';

        // Calling url using curl
        $curl = curl_init();

        curl_setopt_array( $curl, array(

            CURLOPT_TIMEOUT => 120,
            CURLOPT_URL => $url,            
        ));

        if ( !curl_exec( $curl )) {

            die ( 'Error: "' . curl_error( $curl ) . '" - Code: ' . curl_errno( $curl ));
        }

        // Get search results
        $result = file_get_contents( $url );

        // Remove the unneccessary strings that wraps the result returned from the API
        $json = substr( $result, strlen( "jsonFlickrApi("), strlen( $result ) - strlen( "jsonFlickrApi(") - 1 );

        $photos = array();
        $data = json_decode( $json, true );

        // Check if the status didn't fail
        if ( $data['stat'] != 'fail' ) {

            /** Return only the data for the photos 
                as that's the only thing that we need
            */
            $photos = $data['photos']['photo'];
            return $photos;
        } else {

            return false;       
        }
    } // end searchPhotos

}

（我在我的页面模板文件中使用的方法调用）

<?php // Flickr search photos test

require_once( 'class.flickr.php' );

global $flickr_key;

$flickr = new Flickr( 'this_is_my_api-key_placeholder...' );

$query = "Event Photo Uploadr";

$results = $flickr->searchPhotos( $query, $tag );
if ( !empty( $results )) {

    foreach( $results as $photo ) {

        $src = "http://farm" . $photo['farm'] . ".static.flickr.com/" . $photo['server'] . '/' . $photo['id'] . '_' . $photo['secret'] . '.jpg';
        ?>

        <img  src="<?php echo $src; ?>"/>

    <?php }                 
}

正如我所说，我是flickr api的新手......到目前为止，我一直很幸运（感谢stackoverflow，Wordpress Answers和开发者朋友），所以任何有用的输入都非常感激！ ;）

Answer 1

好吧，这听起来很傻，但真正的问题是我错过了=。我不是在开玩笑，我有这个$url .= '&format' . $this->format;（这使得api，默认返回xml）应该是这个$url .= '&format=' . $this->format;（这是抓住我的$format var的正确方法）。我还清理了我的代码......

（主要的flickr功能文件）

<?php

class Flickr{

private $flickr_key;
private $flickr_secret;
private $format = 'json';

// Setting up flickr_key and flickr_secret
public function __construct( $flickr_key ) {

    $this->flickr_key = $flickr_key;
}

public function searchPhotos( $query = '', $tags = '' ){ // Begin searchPhotos 

    $urlencoded_tags = array( 'animals', 'design', 'phones');

    if ( !empty( $args )) {

        $tags_r = explode( ',', $tags );
        foreach ( $tags_r as $tag ) {

            $urlencoded_tags[] = urlencode( $tag );
        }
    }

    // Construct the url
    $url  = 'http://api.flickr.com/services/rest/?';
    $url .= 'method=flickr.photos.search';
    $url .= '&text=' . urlencode( $query );
    $url .= '&tags=' . implode( ',', $urlencoded_tags );
    $url .= '&sort=relevance';
    $url .= '&safe_search=1';
    $url .= '&content_type=4';
    $url .= '&api_key=' . $this->flickr_key;
    $url .= '&format=' . $this->format;
    $url .= '&per_page=10';

    // Get search results
    $result = file_get_contents( $url );

    // Remove the unnecessary strings that wraps the result returned from the API
    $json = substr( $result, strlen( "jsonFlickrApi(" ), strlen( $result ) - strlen( "jsonFlickrApi(" ) - 1 );

    $photos = array();
    $data = json_decode( $json, true );

    // Check if the status didn't fail
    if ( $data['stat'] != 'fail' ) {

        // Return only the data for the photos as that's the only thing that we need
        $photos = $data['photos']['photo'];
        return $photos;

    } else {

        return false;       
    }
} // end searchPhotos

}

我在方法调用中更改的唯一内容是添加alt标记，如alt="<?php echo $photo['title']?>"，并在else语句echo "Failed to construct url successfully";中添加错误消息。

为什么从flickr抓取的图像不会显示？

1 个答案: