Question

我有这些数据，我必须按价格分组，并检查数据的范围和连续性

date            price
2014-01-01  10
2014-01-02  10
2014-01-03  10
2014-01-05  20
2014-01-07  30
2014-01-08  40
2014-01-09  50
2014-01-10  30

，输出应该如下所示

2014-01-01  2014-01-03  10
2014-01-05  2014-01-05  20
2014-01-07  2014-01-07  30
2014-01-08  2014-01-08  40
2014-01-09  2014-01-09  50
2014-01-10  2014-01-10  30

到目前为止我试过了

 var result = list
                .OrderBy(a => a.Date)
                .GroupBy(a => a.Price)
                .Select(x => new
                {
                    DateMax = x.Max(a => a.Date),
                    DateMin = x.Min(a => a.Date),
                    Count = x.Count()
                })
                .ToList()
                .Where(a => a.DateMax.Subtract(a.DateMin).Days == a.Count)
                .ToList();

我不确定这会照顾到连续的约会。所有日期都是独特的！

Answer 1

首先，我们将使用辅助方法对连续项进行分组。它将获得一个将被赋予“之前”和“当前”项目的函数，然后它将确定该项目是否应该在当前组中，或者应该开始一个新项目。

public static IEnumerable<IEnumerable<T>> GroupWhile<T>(
    this IEnumerable<T> source, Func<T, T, bool> predicate)
{
    using (var iterator = source.GetEnumerator())
    {
        if (!iterator.MoveNext())
            yield break;

        List<T> list = new List<T>() { iterator.Current };

        T previous = iterator.Current;

        while (iterator.MoveNext())
        {
            if (predicate(previous, iterator.Current))
            {
                list.Add(iterator.Current);
            }
            else
            {
                yield return list;
                list = new List<T>() { iterator.Current };
            }

            previous = iterator.Current;
        }
        yield return list;
    }
}

现在我们可以使用该方法对项目进行分组，然后选择我们需要的信息：

var query = data.OrderBy(item => item.Date)
                .GroupWhile((previous, current) => 
                    previous.Date.AddDays(1) == current.Date
                    && previous.Price == current.Price)
                .Select(group => new
                {
                    DateMin = group.First().Date,
                    DateMax = group.Last().Date,
                    Count = group.Count(),
                    Price = group.First().Price,
                });

Answer 2

作为Servy's answer的替代品，我发现它更优雅，显然更可靠，

你可以在一次扫描中做更多的定制（订购后）。

 public class ContiguousValuePeriod<TValue>
 {
     private readonly DateTime start;
     private readonly DateTime end;
     private readonly TValue value;

     public ContiguousValuePeriod(
             DateTime start,
             DateTime end,
             TValue value)
     {
         this.start = start;
         this.end = end;
         this.value = value;
     }

     public DateTime Start { get { return this.start; } }
     public DateTime End { get { return this.start; } }
     public TValue Value { get { return this.value; } }
 }

 public IEnumerable<ContiguousValuePeriod<TValue>>
                     GetContiguousValuePeriods<TValue, TItem>(
         this IEnumerable<TItem> source,
         Func<TItem, DateTime> dateSelector,
         Func<TItem, TValue> valueSelector)
 {
     using (var iterator = source
             .OrderBy(t => valueSelector(t))
             .ThenBy(t => dateSelector(t))
             .GetEnumerator())
     {
         if (!iterator.MoveNext())
         {
             yield break;
         }

         var periodValue = valueSelector(iterator.Current); 
         var periodStart = dateSelector(iterator.Current);
         var periodLast = periodStart;
         var hasTail = false;

         while (iterator.MoveNext())
         {
              var thisValue = valueSelector(iterator.Current);
              var thisDate = dateSelector(iterator.Current);

              if (!thisValue.Equals(periodValue)  ||
                   thisDate.Subtract(periodLast).TotalDays > 1.0)
              {
                  // Period change
                  yield return new ContiguousValuePeriod(
                      periodStart,
                      periodLast,
                      periodValue);
                  periodStart = thisDate;
                  periodValue = thisValue;
                  hasTail = false;
              }
              else
              {
                  hasTail = true;
              }

              periodLast = thisDate;
          }
      }

      if (hasTail)
      {
          yield return new ContiguousValuePeriod(
                      periodStart,
                      periodLast,
                      periodValue);
      }
  }

你使用的

，

var result = yourList.GetContiguousValuePeriods(
    a => a.Date,
    a => a.Price);

使用linq获取分组的日期范围

2 个答案: