我必须为我的CS类简介编写一个程序作为项目。该计划必须
我以为我已经完成了程序，但是当我执行程序时，数字从不随机，所有二十个数字都与我输入emacs的最大值相同。当然，在这种情况下，平均值也与最大值相同。到目前为止，这是我的计划......
import java.util.Scanner;
import java.util.Random;
public class CS_ProjectOne
{
public static void main(String[] args)
{
int minimum_integer;
int maximum_integer;
int rn1;
int rn2;
int rn3;
int rn4;
int rn5;
int rn6;
int rn7;
int rn8;
int rn9;
int rn10;
int rn11;
int rn12;
int rn13;
int rn14;
int rn15;
int rn16;
int rn17;
int rn18;
int rn19;
int rn20;
double total;
double average;
Scanner keeper;
Scanner keeper2;
Random gen;
gen = new Random();
keeper = new Scanner(System.in);
System.out.print("Please enter an integer for the MINIMUM value: ");
minimum_integer = keeper.nextInt();
keeper2 = new Scanner(System.in);
System.out.print("Please enter an integer for the MAXIMUM value: ");
maximum_integer = keeper2.nextInt();
rn1 = gen.nextInt();
rn1 = rn1 % minimum_integer + maximum_integer;
rn2 = gen.nextInt();
rn2 = rn2 % minimum_integer + maximum_integer;
rn3 = gen.nextInt();
rn3 = rn3 % minimum_integer + maximum_integer;
rn4 = gen.nextInt();
rn4 = rn4 % minimum_integer + maximum_integer;
rn5 = gen.nextInt();
rn5 = rn5 % minimum_integer + maximum_integer;
rn6 = gen.nextInt();
rn6 = rn6 % minimum_integer + maximum_integer;
rn7 = gen.nextInt();
rn7 = rn7 % minimum_integer + maximum_integer;
rn8 = gen.nextInt();
rn8 = rn8 % minimum_integer + maximum_integer;
rn9 = gen.nextInt();
rn9 = rn9 % minimum_integer + maximum_integer;
rn10 = gen.nextInt();
rn10 = rn10 % minimum_integer + maximum_integer;
rn11 = gen.nextInt();
rn11 = rn11 % minimum_integer + maximum_integer;
rn12 = gen.nextInt();
rn12 = rn12 % minimum_integer + maximum_integer;
rn13 = gen.nextInt();
rn13 = rn13 % minimum_integer + maximum_integer;
rn14 = gen.nextInt();
rn14 = rn14 % minimum_integer + maximum_integer;
rn15 = gen.nextInt();
rn15 = rn15 % minimum_integer + maximum_integer;
rn16 = gen.nextInt();
rn16 = rn16 % minimum_integer + maximum_integer;
rn17 = gen.nextInt();
rn17 = rn17 % minimum_integer + maximum_integer;
rn18 = gen.nextInt();
rn18 = rn18 % minimum_integer + maximum_integer;
rn19 = gen.nextInt();
rn19 = rn19 % minimum_integer + maximum_integer;
rn20 = gen.nextInt();
rn20 = rn20 % minimum_integer + maximum_integer;
System.out.println("Your random numbers are: " + rn1 + ", " + rn2 + ", " + rn3 + ", " + rn4 + ", " + rn5 + ", " + rn6 + ", " + rn7 + ", " + rn8 + ", " + rn9 + ", " + rn10 + ", " + rn11 + ", " + rn12 + ", " + rn13 + ", " + rn14 + ", " + rn15 + ", " + rn16 + ", " + rn17 + ", " + rn18 + ", " + rn19 + ", " + rn20 + ".");
total = rn1 + rn2 + rn3 + rn4 + rn5 + rn6 + rn7 + rn8 + rn9 + rn10 + rn11 + rn12 + rn13 + rn14 + rn15 + rn16 + rn17 + rn18 + rn19 + rn20;
average = total / 20;
System.out.print("The average is " + average);
}
}
任何人都可以提供一些帮助并引导我朝着正确的方向前进吗？我确定有些东西我做得不对（或很多东西）我只是不知道到底是什么。
这是我试图让它工作的更短版本......
import java.util.Random;
import java.util.Scanner;
public class p1
{
public static void main(String[] args)
{
Random gen;
gen = new Random();
Scanner keeper;
int range, user_min, user_max, num1, num2, num3, total;
double average;
keeper = new Scanner(System.in);
System.out.print("Please enter a maximum integer value: ");
user_max = keeper.nextInt();
keeper = new Scanner(System.in);
System.out.print("Please enter a minimum integer value: ");
user_min = keeper.nextInt();
range = user_max - user_min + 1;
num1 = gen.nextInt() % range + user_min;
num2 = gen.nextInt() % range + user_min;
num3 = gen.nextInt() % range + user_min;
System.out.print("The random numbers computed are " + num1 + ", " + num2 + ", " + num3 + ", ");
}
}
为什么不能处理否定？我的值仍不在指定的范围内？ HELP？
答案 0 :(得分：2)
一些提示/提示：
对20个数字使用数组。然后当你发现错误时，你只需要纠正一次而不是20次。
随机数生成器有种子。确保每次都提供不同的种子，否则随机数生成器将始终生成相同的随机数。
MIN和MAX之间可以有多少个值？例如，3到7之间可以有多少个不同的值？ 45和80？ 3和1200？找到模式。
了解您的程序需要'％'运算符的原因。通过“gen.nextInt（）％NUM”实现了什么？
答案 1 :(得分：1)
随机列表示例：
（在Python中代替Java，以便于演示。）
1 #!/usr/bin/env python
2 def spawn(user_min, user_max, rounds):
3 import random
4 sum = 0
5 user_range = user_max - user_min + 1
6 for i in range(rounds):
7 result = int((random.random() * user_range)) + user_min
8 sum = sum + result
9 print(str(i) + ': ' + str(result))
10 mean = sum / rounds
11 print('range: ' + str(user_range))
12 print('mean: ' + str(mean))
您感兴趣的行是：
[0.0, 1.0)的随机值;乘以所需的用户范围;然后转换为整数以“切掉”尾随小数点;然后将结果添加到范围的最小允许值。例如：
range = (10) - (-5) + 1 = 16
a_result = (int)(0.14159265359 * 16) + -5 = 3 - 5 = -3
another_result = (int)(0.71828182845 * 16) + -5 = 11 - 5 = 6
答案 2 :(得分：0)
该行
rn1 = rn1 % minimum_integer + maximum_integer;
错了。例如，考虑生成1到6范围内的数字。然后计算
rn1 = rn1 % 1 + 6;
现在，rn1 % 1总是等于0，所以你总是得到6.你应该使用不同的公式。
答案 3 :(得分：0)
这就是我想出的......
import java.util.*;
class RandNegToPos {
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
int array[]=new int[20];
System.out.println("What is the minimum? ");
int min = scan.nextInt();
System.out.println("What is the maximum? ");
int max = scan.nextInt();
if (max < min)
System.out.println("Sorry the maximum is less than the miniumum.");
else{
int rnd = (int) (min + Math.random() * ((max) - min));
for (int i=0; i < 20 ; i++)
{
rnd = (int) (min + Math.random() * ((max) - min));
array[i] = rnd;
}
int sum=0;
for (int t : array)
sum += t;
System.out.println("Your randoms are:");
System.out.println(Arrays.toString(array));
System.out.println("The average is: " + (sum/20) );
}
}
}