如果我有一个阵列:
$data = array(
array(
'manufacturers_id' => 29,
'manufacturers_name' => 'Quicksilver',
'products_quantity' => 1,
'products_price' => 15.6000,
'products_cost' => 8.0000,
),
array(
'manufacturers_id' => 29,
'manufacturers_name' => 'Quicksilver',
'products_quantity' => 2,
'products_price' => 4.6722,
'products_cost' => 2.4000,
)
);
如何重新格式化以提供结构
Array
(
[Quiksilver] => Array
(
[brands_sales] => $brandsSalesVal
[brands_products_sold] => $brandsSoldVal
[brands_costs] => $brandsCostsVal
)
$brandsSalesVal
=所有products_price * products_quantity(每个manufacturer_id)的总和
$brandsSoldVal
=每个制造商的所有products_quantity的总和
$brandsCostsVal
=每个制造商的所有products_costs的总和
非常感谢任何帮助,我感谢任何人花时间回答我相当冗长的问题。我仍然需要重新格式化阵列。
答案 0 :(得分:2)
您需要使用foreach
循环,如下所示:
// Declare the totals array and
// the manufacturers->id map
$totals = array();
$manufacturers = array();
// Loop through the array of products and populate
// the totals array
foreach($data as $value){
// Set the key to the manufacturers name
$key = $value['manufacturers_name'];
// If the array has not been built yet, then ensure the
// values are set to 0 and add the manufacturer to the
// manufacturers map if it is not already there
if(!isset($totals[$key])){
// Add the manufacturer to the map
$manufacturers[$value['manufacturers_id']] = $key;
// Default the values to 0
$totals[$key]['brand_sales'] = 0;
$totals[$key]['brands_products_sold'] = 0;
$totals[$key]['brands_costs'] = 0;
}
// Calculate the brand sales
$totals[$key]['brand_sales'] += ($value['products_price']*$value['products_quantity']);
// Calculate the brand sales
$totals[$key]['brands_products_sold'] += $value['products_quantity'];
// Calculate the brand sales
$totals[$key]['brands_costs'] += $value['products_cost'];
}
为了访问存储在上面生成的数组中的信息,您可以使用其他foreach
循环,如下所示:
// Loop through the $totals array and print the result
foreach($totals as $key => $value){
// Print the manufacturers name and ID
echo "\n".$key." (ID: ".array_search($key,$manufacturers).")";
// Print the totals for the current manufacturer
echo "\n\tBrand Sales: ".$values['brand_sales'];
echo "\n\tBrand Products Sold: ".$values['brands_products_sold'];
echo "\n\tBrand Costs: ".$values['brands_costs'];
}
array_search
函数用于根据$manufacturers
数组中存储的制造商名称查找制造商的ID。您可以更改代码,使其不需要array_search
功能,但我这样做是因为传统上您会映射ID-> NAME,而不是NAME-> ID。这只是个人偏好......
有关foreach
循环的详细信息,请参阅here
答案 1 :(得分:0)
$data = array(
array(
'manufacturers_id' => 29,
'manufacturers_name' => 'Quicksilver',
'products_quantity' => 1,
'products_price' => 15.6000,
'products_cost' => 8.0000,
),
array(
'manufacturers_id' => 29,
'manufacturers_name' => 'Quicksilver',
'products_quantity' => 2,
'products_price' => 4.6722,
'products_cost' => 2.4000,
)
,
array(
'manufacturers_id' => 30,
'manufacturers_name' => 'Different Brand',
'products_quantity' => 2,
'products_price' => 4.6722,
'products_cost' => 2.4000,
)
);
$sortedData = array();
foreach($data as $num => $row){
$manufacturersName = $row['manufacturers_name'];
//If we don't have an array made for the manufacturer yet, make one
if(!isset($sortedData[$manufacturersName])){
$sortedData[$manufacturersName] = array(
'brands_sales' => 0,
'brands_products_sold' => 0,
'brands_costs' => 0
);
};
//Make a reference to the relevant manufacturer sorted data
$manufacturerData = &$sortedData[$manufacturersName];
$qty = $row['products_quantity'];
//
$manufacturerData['brands_sales'] += $qty * $row['products_price'];
$manufacturerData['brands_products_sold'] += $qty;
$manufacturerData['brands_costs'] += $row['products_cost'];
}
var_dump($sortedData); // <- your result.
结果:
array (size=2)
'Quicksilver' =>
array (size=3)
'brands_sales' => float 24.9444
'brands_products_sold' => int 3
'brands_costs' => float 10.4
'Different Brand' =>
array (size=3)
'brands_sales' => float 9.3444
'brands_products_sold' => int 2
'brands_costs' => float 2.4