Question

我有这个：

vehicles = vehicles.Where(x => x.ModelUrl == filter.ModelUrl);

这很好，但是我没有传递一个字符串（作为filter.ModelUrl），而是传递一个List，查询应该返回所有结果，其中x.ModelUrl是列表中的任何项目。

我该怎么做？

由于

Answer 1

vehicles = vehicles.Where(x => OtherList.Contains(x.ModelUrl));

或

vehicles = vehicles.Where(x => OtherList.Any(ol => ol.ModelUrl == x.ModelUrl));

Answer 2

vehicles = vehicles.Where(x => list.Contains(x.ModelUrl));

Answer 3

欢迎

vehicles = vehicles.Where(x => list.Contains(x.ModelUrl));

Answer 4

Where / Contains方法的替代方法是使用Join：

vehicles = vehicles.Join(yourListOfUrls, 
                         vec => vec.ModelUrl,
                         url => url,
                         (vev, url) => vec);

或

vehicles = from vec in vehicles
           join url in yourListOfUrls on vec.ModelUrl Equals url
           select vec

对于更大的列表更快。

Answer 5

也许你应该只使用方法Contains：

var vehicles = vehicles.Where(x => filter.Contains(x.ModelUrl));

Answer 6

vehicles = vehicles.Where(x => list.Contains(x.ModelUrl));

Linq - 过滤多个可能的等值

6 个答案: