正则表达式匹配书名 - 组

时间:2013-10-18 06:11:01

标签: java regex

我写了一个正则表达式:

value='[A-Za-z]+\\,[0-9]+\\,([A-Za-z0-9]+)\\,([A-Za-z0-9]+)'>[A-Za-z0-9]+\\s-\\s(.*)?\\s\\(

它运作得相当不错,但问题是它的最后一直保持匹配...

例如,它应该在书籍上工作,我正在测试它如下:

value='C,201301,F110,JEWL1050'>JEWL1050 - Industry Skills I (F110)</option>
value='C,201301,F114,JEWL1050'>JEWL1050 - Industry Skills I (F114)</option>
value='C,201301,F114,JEWL1054'>JEWL1054 - Jewellery Rendering & Illustra (F114)</option>
value='C,201301,F110,JEWL2029'>JEWL2029 - Production Techniques B (F110)</option>
value='C,201301,F114,JEWL2029'>JEWL2029 - Production Techniques B (F114)</option>
value='C,201301,LIAD,LANG9066'>LANG9066 - Italian For Beginners (LIAD)</option>
value='C,201301,T302,LAW1151'>LAW1151 - Canandian & Environmental Law (T302)</option>
value='C,201301,T305,LAW1151'>LAW1151 - Canandian & Environmental Law (T305)</option>
value='C,201301,F402,LAW1152'>LAW1152 - International Law & Agreements (F402)</option>
value='C,201301,T302,LAW3201'>LAW3201 - Protection Legislation (T302)</option>
value='C,201301,T303,LAW3201'>LAW3201 - Protection Legislation (T303)</option>
value='C,201301,T304,LAW3201'>LAW3201 - Protection Legislation (T304)</option>

因此,对于第一本书,它应该将F110视为第1组,将JEWL1050视为第2组,将Industry Skills I视为第3组。

然而,它正确捕获前两组但不捕获最后一组。它会捕获- Industry Skills I (F110)</option>而不是..

我有什么想法可以修复我的正则表达式?我似乎无法完成最后一组。 请帮我。先谢谢你。

3 个答案:

答案 0 :(得分:1)

从理论上讲,这应该按原样运作。

以下是您提出的正则表达式(由于工具与Java代码的性质,\\已更改为\)应用于您的示例输入时:http://regex101.com/r/hL8pZ8

这个工具也提供了一个“Java”复选框,甚至是相应的Java代码,虽然没有永久链接所以你必须输入正则表达式(再次使用\\而不是\)并自己提供样本数据:http://www.myregextester.com/index.php

那就是说,对于子孙后代,这是它的输出:

Raw Match Pattern:

  value='[A-Za-z]+\,[0-9]+\,([A-Za-z0-9]+)\,([A-Za-z0-9]+)'>[A-Za-z0-9]+\s-\s(.*)?\s\(

Java Code Example:

import java.util.regex.Pattern;
import java.util.regex.Matcher;
class Module1{
  public static void main(String[] asd){
    String sourcestring = "source string to match with pattern";
    Pattern re = Pattern.compile("value='[A-Za-z]+\\,[0-9]+\\,([A-Za-z0-9]+)\\,([A-Za-z0-9]+)'>[A-Za-z0-9]+\\s-\\s(.*)?\\s\\(");
    Matcher m = re.matcher(sourcestring);
    int mIdx = 0;
    while (m.find()){
      for (int groupIdx = 0; groupIdx < m.groupCount()+1; groupIdx++){
        System.out.println( "[" + mIdx + "][" + groupIdx + "] = " + m.group(groupIdx));
      }
      mIdx++;
    }
  }
}

$matches Array:
(
  [0] => Array
    (
      [0] => value='C,201301,F110,JEWL1050'>JEWL1050 - Industry Skills I (
      [1] => value='C,201301,F114,JEWL1050'>JEWL1050 - Industry Skills I (
      [2] => value='C,201301,F114,JEWL1054'>JEWL1054 - Jewellery Rendering & Illustra (
      [3] => value='C,201301,F110,JEWL2029'>JEWL2029 - Production Techniques B (
      [4] => value='C,201301,F114,JEWL2029'>JEWL2029 - Production Techniques B (
      [5] => value='C,201301,LIAD,LANG9066'>LANG9066 - Italian For Beginners (
      [6] => value='C,201301,T302,LAW1151'>LAW1151 - Canandian & Environmental Law (
      [7] => value='C,201301,T305,LAW1151'>LAW1151 - Canandian & Environmental Law (
      [8] => value='C,201301,F402,LAW1152'>LAW1152 - International Law & Agreements (
      [9] => value='C,201301,T302,LAW3201'>LAW3201 - Protection Legislation (
      [10] => value='C,201301,T303,LAW3201'>LAW3201 - Protection Legislation (
      [11] => value='C,201301,T304,LAW3201'>LAW3201 - Protection Legislation (
    )

  [1] => Array
    (
      [0] => F110
      [1] => F114
      [2] => F114
      [3] => F110
      [4] => F114
      [5] => LIAD
      [6] => T302
      [7] => T305
      [8] => F402
      [9] => T302
      [10] => T303
      [11] => T304
    )

  [2] => Array
    (
      [0] => JEWL1050
      [1] => JEWL1050
      [2] => JEWL1054
      [3] => JEWL2029
      [4] => JEWL2029
      [5] => LANG9066
      [6] => LAW1151
      [7] => LAW1151
      [8] => LAW1152
      [9] => LAW3201
      [10] => LAW3201
      [11] => LAW3201
    )

  [3] => Array
    (
      [0] => Industry Skills I
      [1] => Industry Skills I
      [2] => Jewellery Rendering & Illustra
      [3] => Production Techniques B
      [4] => Production Techniques B
      [5] => Italian For Beginners
      [6] => Canandian & Environmental Law
      [7] => Canandian & Environmental Law
      [8] => International Law & Agreements
      [9] => Protection Legislation
      [10] => Protection Legislation
      [11] => Protection Legislation
    )
)

答案 1 :(得分:1)

这是一个更复杂的正则表达式。

value='(?:[^,]+,){2}([^,]+),([^,]+)'>[^-]+-\s+([^(]+)(?=\s)

请参阅live demo

答案 2 :(得分:1)

我已经检查过不需要C,201301。因此,一个简单的解决方案是将<>之间的值视为垃圾,仅关注><

<option value='C,201301,T302,LAW3201'>LAW3201 - Protection Legislation (T302)</option>
<option value='C,201301,T303,LAW3201'>LAW3201 - Protection Legislation (T303)</option>
<option value='C,201301,T304,LAW3201'>LAW3201 - Protection Legislation (T304)</option>

这表明:

>([A-Z]+[0-9])+\\s-\\s(.*)?\\s([A-Z0-9]+)<

作为三个群体的充分表达。