Question

我正在使用c＃和sql在MVC4中完成我的项目..我有一个表MemberDetails，其中包含表

CREATE TABLE [dbo].[MemberDetails] (
[Id]          INT           IDENTITY (1, 1) NOT NULL,
[Mem_FirstNA] VARCHAR (100) NOT NULL,
[Mem_LastNA]  VARCHAR (100) NOT NULL,
[Mem_Occ]     VARCHAR (100) NOT NULL,
[Mem_DOB]     DATETIME      NOT NULL,
[Mem_Email]   VARCHAR (50)  NOT NULL,
PRIMARY KEY CLUSTERED ([Id] ASC)
 );

我只想选择未来30天生日的姓名和出生日期，并使用以下查询

SELECT 
    Mem_FirstNA, Mem_LastNA, Mem_DOB 
FROM 
    MemberDetails 
WHERE 
    Mem_DOB >= getdate() - 1 AND Mem_DOB <= getdate() + 30

这是否正确，我选择了0项，我使用下表。

 1  Pal Software    08-03-1987 AM 12:00:00
 3  mn  Par Bussiness   19-10-1967 AM 12:00:00
 4  man George  Business    13-11-1956 AM 12:00:00
 5  Smi Kan Housewife   22-10-1980 AM 12:00:00

Answer 1

更新

SELECT 
    Mem_FirstNA, Mem_LastNA, Mem_DOB 
FROM 
    MemberDetails 
WHERE 
    DATEDIFF(DAY, GETDATE(), DATEADD(YEAR, DATEDIFF(YEAR, Mem_DOB, GETDATE()), Mem_DOB)) BETWEEN 0 AND 30

Answer 2

试试这个

        SELECT 
           Mem_FirstNA, Mem_LastNA, Mem_DOB
        FROM 
             MemberDetails 
       WHERE DAYOFYEAR(Mem_DOB)-DAYOFYEAR(getdate())<=30

Answer 3

SELECT 
    Mem_FirstNA, Mem_LastNA, Mem_DOB 
FROM 
    MemberDetails 
WHERE 
    Mem_DOB >= Cast(current_timestamp As Date) AND Mem_DOB < DATEADD(d, 30, Cast(current_timestamp As Date));

Answer 4

应该有效。根据评论删除使用之间。也适用于1月份的出生日期

DECLARE @now DATETIME
    SET @now = GETDATE()

 SELECT Mem_FirstNA, Mem_LastNA, Mem_DOB
   FROM MemberDetails
  WHERE 
   CASE WHEN month(Mem_DOB) = 1
   THEN DATEADD(YY, YEAR(DATEADD(DAY, 30, DATEADD(m,  month(@now) - 1, DAY(@now) - 1))) - 1900, DATEADD(m,  month(Mem_DOB) - 1, DAY(Mem_DOB) - 1))
   ELSE DATEADD(m,  month(Mem_DOB) - 1, DAY(Mem_DOB) - 1)
    END
      > DATEADD(m,  month(@now) - 1, DAY(@now) - 1) 
    AND 
   CASE WHEN month(Mem_DOB) = 1
   THEN DATEADD(YY, YEAR(DATEADD(DAY, 30, DATEADD(m,  month(@now) - 1, DAY(@now) - 1))) - 1900, DATEADD(m,  month(Mem_DOB) - 1, DAY(Mem_DOB) - 1))
   ELSE DATEADD(m,  month(Mem_DOB) - 1, DAY(Mem_DOB) - 1)
    END
      < DATEADD(DAY, 30, DATEADD(m,  month(@now) - 1, DAY(@now) - 1))

希望有所帮助

Answer 5

试试这个

SELECT 
    Mem_FirstNA, Mem_LastNA, Mem_DOB 
FROM 
    MemberDetails 
WHERE 
    WHERE DATEPART(mm,Mem_DOB) BETWEEN DATEPART(mm,getDate()) AND DATEPART(mm,getDate())+1;

Answer 6

为什么不使用where where子句：

WHERE MEM_DOB BETWEEN GETDATE()-1 AND GETDATE()+30

Answer 7

试试这个...... SELECT Mem_FirstNA，Mem_LastNA，Mem_DOB 从 MemberDetails 哪里 ltrim（str（year（GETDATE（））））+' - '+ ltrim（str（month（Mem_DOB）））+' - '+ ltrim（str（day（Mem_DOB）））＆gt; = getdate（） - 1 AND ltrim（str（year（GETDATE（））））+' - '+ ltrim（str（month（Mem_DOB）））+' - '+ ltrim（str（day（Mem_DOB）））＆lt; = getdate（）+ 30

编辑：对这个答案的评论正确地指出，如果当年是闰年，它将无法运作。所以这个更新。使用Get a list of dates between two dates using a function

可以更有效地生成日期列表

Select Mem_FirstNA, Mem_LastNA, Mem_DOB from MemberDetails m, (
Select datepart(dd,getdate()) as d,  datepart(mm,getdate()) as m
union
Select datepart(dd,getdate() + 1) as d,  datepart(mm,getdate() + 1) as m
union
Select datepart(dd,getdate() + 2) as d,  datepart(mm,getdate() + 2) as m
union
Select datepart(dd,getdate() + 3) as d,  datepart(mm,getdate() + 3) as m
union
Select datepart(dd,getdate() + 4) as d,  datepart(mm,getdate() + 4) as m
union
Select datepart(dd,getdate() + 5) as d,  datepart(mm,getdate() + 5) as m
union
Select datepart(dd,getdate() + 6) as d,  datepart(mm,getdate() + 6) as m
union
Select datepart(dd,getdate() + 7) as d,  datepart(mm,getdate() + 7) as m
union
Select datepart(dd,getdate() + 8) as d,  datepart(mm,getdate() + 8) as m
union
Select datepart(dd,getdate() + 9) as d,  datepart(mm,getdate() + 9) as m
union
Select datepart(dd,getdate() + 10) as d,  datepart(mm,getdate() + 10) as m
union
Select datepart(dd,getdate() + 11) as d,  datepart(mm,getdate() + 11) as m
union
Select datepart(dd,getdate() + 12) as d,  datepart(mm,getdate() + 12) as m
union
Select datepart(dd,getdate() + 13) as d,  datepart(mm,getdate() + 13) as m
union
Select datepart(dd,getdate() + 14) as d,  datepart(mm,getdate() + 14) as m
union
Select datepart(dd,getdate() + 15) as d,  datepart(mm,getdate() + 15) as m
)X
where   
datepart(dd, m.Mem_DOB) = x.d and datepart(mm, m.Mem_DOB) = x.m

如果您正在进行投票，请评论原因。

如何从SQL表中获取30天后的日期

7 个答案: