我无法正确编写此功能。它应该递归地列出第一个参数提供的路径的内容(如ls -R),但它会很快停止。这是代码,预期输出和我得到的输出:
int browseDir (const char *path, const int *options)
{
char callingdir[MAXDIRLEN];
char currentdir[MAXDIRLEN];
getcwd(callingdir,MAXDIRLEN);
DIR *dirstream;
struct dirent *dir_entry;
struct stat file_data;
LIST subd_list = newList();
if (path == NULL)
strcpy(currentdir,callingdir);
else
strcpy(currentdir,path);
dirstream = opendir(currentdir);
printf("Listing: %s\n",currentdir);
chdir(currentdir);
if (dirstream == NULL)
{
perror("Error: cannot open directory\n");
return 0;
}
while((dir_entry = readdir(dirstream)) != NULL)
{
if (!ISSET_A_FLAG(*options))
{
if (dir_entry->d_name[0]=='.')
continue;
}
if (!ISSET_S_FLAG(*options))
{
stat(dir_entry->d_name, &file_data);
printStat(&file_data);
}
printf("%s ",dir_entry->d_name);
printf("\n");
if (ISSET_R_FLAG(*options) && (dir_entry->d_type & DT_DIR) && strcmp(dir_entry->d_name,".") && strcmp(dir_entry->d_name,".."))
addNode(subd_list, dir_entry->d_name);
}
closedir(dirstream);
while(!isEmpty(subd_list))
{
browseDir((*subd_list)->data, options);
delNode(subd_list);
}
chdir(callingdir);
return 0;
}
使用ls -Rli(预期)输出
tod@iTod:~/Dropbox/programming/SO/myshell2$ ls -lRi /home/tod/programming/shelldeb
/home/tod/programming/shelldeb:
totale 52
1150597 drwxr-xr-x 3 tod tod 4096 ott 18 02:34 bin
1054396 -rw-rw-r-- 1 tod tod 7696 ott 18 15:21 commands.c
1045205 -rw-rw-r-- 1 tod tod 1233 ott 16 23:14 commands.h
1045208 -rw-rw-r-- 1 tod tod 952 ott 18 17:10 list.c
1057517 -rw-rw-r-- 1 tod tod 244 ott 18 15:22 list.h
1055205 -rw-r--r-- 1 tod tod 487 ott 18 02:36 main.c
1150595 drwxr-xr-x 3 tod tod 4096 ott 18 02:34 obj
1057590 -rw-rw-r-- 1 tod tod 1213 ott 18 09:33 parsing.c
1057622 -rw-rw-r-- 1 tod tod 193 ott 18 09:33 parsing.h
1055154 -rw-rw-r-- 1 tod tod 1368 ott 18 02:51 shelldeb.cbp
1057688 -rw-rw-r-- 1 tod tod 665 ott 18 15:22 shelldeb.depend
1057721 -rw-rw-r-- 1 tod tod 1413 ott 18 23:20 shelldeb.layout
/home/tod/programming/shelldeb/bin:
totale 4
1150598 drwxr-xr-x 3 tod tod 4096 ott 20 14:02 Debug
/home/tod/programming/shelldeb/bin/Debug:
totale 4
1150684 drwxrwxr-x 4 tod tod 4096 ott 20 14:02 r55
/home/tod/programming/shelldeb/bin/Debug/r55:
totale 8
1150685 drwxrwxr-x 2 tod tod 4096 ott 20 14:03 tmpfolder
1150686 drwxrwxr-x 2 tod tod 4096 ott 20 14:02 tmpfolder2
/home/tod/programming/shelldeb/bin/Debug/r55/tmpfolder:
totale 0
1045360 -rw-rw-r-- 1 tod tod 0 ott 20 14:03 myfile
/home/tod/programming/shelldeb/bin/Debug/r55/tmpfolder2:
totale 0
/home/tod/programming/shelldeb/obj:
totale 4
1150596 drwxr-xr-x 3 tod tod 4096 ott 20 14:01 Debug
/home/tod/programming/shelldeb/obj/Debug:
totale 20
1046334 -rw-rw-r-- 1 tod tod 15088 ott 18 17:10 commands.o
1046232 -rw-rw-r-- 1 tod tod 0 ott 20 14:01 comment.txt
1150683 drwxrwxr-x 2 tod tod 4096 ott 20 14:02 tmpfolder
/home/tod/programming/shelldeb/obj/Debug/tmpfolder:
运行我的shell的当前输出:
> list /home/tod/programming/shelldeb -r
Listing: /home/tod/programming/shelldeb
1057517 -rw-rw-r-- 1 1000 1000 244 list.h
1054396 -rw-rw-r-- 1 1000 1000 7696 commands.c
1057590 -rw-rw-r-- 1 1000 1000 1213 parsing.c
1150597 drwxr-xr-x 3 1000 1000 4096 bin
1045208 -rw-rw-r-- 1 1000 1000 952 list.c
1055154 -rw-rw-r-- 1 1000 1000 1368 shelldeb.cbp
1150595 drwxr-xr-x 3 1000 1000 4096 obj
1045205 -rw-rw-r-- 1 1000 1000 1233 commands.h
1057688 -rw-rw-r-- 1 1000 1000 665 shelldeb.depend
1057721 -rw-rw-r-- 1 1000 1000 1413 shelldeb.layout
1057622 -rw-rw-r-- 1 1000 1000 193 parsing.h
1055205 -rw-r--r-- 1 1000 1000 487 main.c
Listing: obj
1150596 drwxr-xr-x 3 1000 1000 4096 Debug
Listing: Debug
1046232 -rw-rw-r-- 1 1000 1000 0 comment.txt
1150683 drwxrwxr-x 2 1000 1000 4096 tmpfolder
1046334 -rw-rw-r-- 1 1000 1000 15088 commands.o
Listing: tmpfolder
1054413 -rw-rw-r-- 1 1000 1000 0 tmp.txt
答案 0 :(得分:1)
我终于设法以一种非常简单的方式编写递归列表函数。我在c标准库中找到了函数nftw(),基本上它完成了所有的工作。 以下是谁可能感兴趣的代码:
static int list (const char *path)
{
char calling_dir[MAXDIRLEN];
DIR *dirstream;
struct dirent *dir_entry;
struct stat file_data;
getcwd(calling_dir,MAXDIRLEN);
dirstream=opendir(path);
if (dirstream == NULL)
{
perror("Error: cannot open directory\n");
return -1;
}
chdir(path);
while((dir_entry = readdir(dirstream)) != NULL)
{
if (!ISSET_A_FLAG(options))
{
if (dir_entry->d_name[0]=='.')
continue;
}
if (!ISSET_S_FLAG(options))
{
stat(dir_entry->d_name, &file_data);
printStat(&file_data);
}
printf("%s ",dir_entry->d_name);
printf("\n");
}
closedir(dirstream);
chdir(calling_dir);
return 0;
}
static int list_R (const char *entry_path, const struct stat *entry_stat,int typeflag,struct FTW *ftwbuf)
{
int status;
if(typeflag & FTW_D)
{
printf("\nContent of %s : \n",entry_path);
status=list(entry_path);
}
if (status == -1)
return status;
return 0;
}
使用这两个函数,您只需实现printstat(),在目录条目上打印信息。 对nftw的简单调用(path,list_R,1,ftw_flags);设置FTW_PHYS标志后完成工作。
答案 1 :(得分:0)
如果你想要一个像ls
这样的程序(它将目录路径作为唯一的参数),那么我认为你过度复杂了,这是我的版本:
struct dirent *file = NULL;
DIR * direc = NULL;
if((direc = opendir(argv[1])) == NULL)
{
perror("");
exit(-1);
}
while((file = readdir(direc)) != NULL)
printf("%s" , file->d_name);
并且你有一个基本的工作ls
程序