Question

我知道这是一个非常基本的问题，但有些我怎么设法找不到解决这个问题的方法。我有一个有主方法的java类。在该方法中，我尝试访问https网址，如下所示：

package helloworld;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.URL;

import javax.net.ssl.HttpsURLConnection;

public class ConnectHttps
{
public static void main(String[] argsd)
{
    System.out.println("***************Https testing started **************");
    try
    {
        URL u = new URL("https://localhost:8443/myapp/test");
        HttpsURLConnection http = (HttpsURLConnection) u.openConnection();
        http.setAllowUserInteraction(true);
        http.setRequestMethod("GET");
        http.connect();

        InputStream is = http.getInputStream();
        BufferedReader reader = new BufferedReader(new InputStreamReader(is));
        StringBuilder stringBuilder = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null)
        {
            stringBuilder.append(line
                + "\n");
        }
        System.out.println(stringBuilder.toString());
        System.out.println("***************Https testing completed **************");
    }
    catch (IOException e)
    {
        System.out.println("***************Https testing failed **************");
        e.printStackTrace();
    }
}

}

执行此程序时，我得到的输出是：

***************Https testing started **************
***************Https testing failed **************
javax.net.ssl.SSLHandshakeException: java.security.cert.CertificateException: No name matching localhost found
at sun.security.ssl.Alerts.getSSLException(Alerts.java:192)
at sun.security.ssl.SSLSocketImpl.fatal(SSLSocketImpl.java:1886)
at sun.security.ssl.Handshaker.fatalSE(Handshaker.java:276)
at sun.security.ssl.Handshaker.fatalSE(Handshaker.java:270)
at sun.security.ssl.ClientHandshaker.serverCertificate(ClientHandshaker.java:1341)
at sun.security.ssl.ClientHandshaker.processMessage(ClientHandshaker.java:153)
at sun.security.ssl.Handshaker.processLoop(Handshaker.java:868)
at sun.security.ssl.Handshaker.process_record(Handshaker.java:804)
at sun.security.ssl.SSLSocketImpl.readRecord(SSLSocketImpl.java:1016)
at sun.security.ssl.SSLSocketImpl.performInitialHandshake(SSLSocketImpl.java:1312)
at sun.security.ssl.SSLSocketImpl.startHandshake(SSLSocketImpl.java:1339)
at sun.security.ssl.SSLSocketImpl.startHandshake(SSLSocketImpl.java:1323)
at sun.net.www.protocol.https.HttpsClient.afterConnect(HttpsClient.java:515)
at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.connect(AbstractDelegateHttpsURLConnection.java:185)
at sun.net.www.protocol.https.HttpsURLConnectionImpl.connect(HttpsURLConnectionImpl.java:153)
at helloworld.ConnectHttps.main(ConnectHttps.java:59)

我想我在这里犯了一个非常基本的错误。

我正在使用JDK 1.7.0_25。

Answer 1

java.net.ConnectException: Connection timed out: connect

这与SSL / TLS无关。相反，您的客户端根本无法连接到服务器（至少不能在合理的时间内）。

防火墙很可能阻止您进行此类连接。

您可能需要通过代理，在这种情况下，https.proxyHost应考虑设置https.proxyPort和HttpsURLConnection系统属性。

如何从Java应用程序访问HTTPS URL

1 个答案: