清除Android中的ListView?

时间:2013-10-17 16:57:27

标签: android listview android-listview

我从数据库中获取第一个数据,listview将显示数据。目前,当多次调用列表时,数据将附加到列表的末尾。

有没有办法清除listview,以便新数据再次位于listView的顶部

public class AndroidTestActivity extends Activity 
{
    JSONArray jArray;
    String result = null;
    InputStream is = null;
    StringBuilder sb=null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        Button b1 = (Button) findViewById(R.id.button1);
        b1.setOnClickListener(new Button.OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                EditText tv = (EditText) findViewById(R.id.editView);
                ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

                //http get
                try{
                    HttpClient httpclient = new DefaultHttpClient();
                    HttpGet httpget = new HttpGet("http://192.168.1.132/test.php");
                    HttpResponse response = httpclient.execute(httpget);
                    HttpEntity entity = response.getEntity();
                    is = entity.getContent();
                }catch(Exception e){
                    Log.e("log_tag", "Error in http connection"+e.toString());
                }

                //convert response to string
                try{
                    BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
                    sb = new StringBuilder();
                    sb.append(reader.readLine() + "\n");

                    String line="0";
                    while ((line = reader.readLine()) != null) {
                        sb.append(line + "\n");
                    }

                    is.close();
                    result=sb.toString();
                }catch(Exception e){
                    Log.e("log_tag", "Error converting result "+e.toString());
                }

                //paring data
                int ct_id;
                String ct_name;        

                try{
                    jArray = new JSONArray(result);
                    JSONObject json_data=null;  

                    for(int i=0;i<jArray.length();i++){
                        json_data = jArray.getJSONObject(i);
                        ct_id=json_data.getInt("id");
                        ct_name=json_data.getString("name");
                        tv.append(ct_name);
                    }
                }catch(JSONException e1){
                //   Toast.makeText(getBaseContext(), "No City Found" ,Toast.LENGTH_LONG).show();
                } catch (ParseException e1) {
                    e1.printStackTrace();
                }
            }
        });
    }
}

4 个答案:

答案 0 :(得分:0)

清除ArryList中使用的任何对象的数组或ListView Adapter。然后再次将新数据加载到Array/ArrayList并调用adapter.notifyDataSetChanged()方法。

答案 1 :(得分:0)

从您想要清除的代码中调用这两种方法 这里的适配器是您在列表中添加它的ArrayAdapter的一个实例。

adapter.clear()
adapter.notifyDataSetChanged()

答案 2 :(得分:0)

每次创建一个新列表并从中获取数据,并仅在此列表中添加旧数据。

答案 3 :(得分:0)

只需写下listView.setAdapter(null)你要清除listview的地方..这对我有用..