我从数据库中获取第一个数据,listview将显示数据。目前,当多次调用列表时,数据将附加到列表的末尾。
有没有办法清除listview,以便新数据再次位于listView的顶部
public class AndroidTestActivity extends Activity
{
JSONArray jArray;
String result = null;
InputStream is = null;
StringBuilder sb=null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button b1 = (Button) findViewById(R.id.button1);
b1.setOnClickListener(new Button.OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
EditText tv = (EditText) findViewById(R.id.editView);
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http get
try{
HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget = new HttpGet("http://192.168.1.132/test.php");
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//paring data
int ct_id;
String ct_name;
try{
jArray = new JSONArray(result);
JSONObject json_data=null;
for(int i=0;i<jArray.length();i++){
json_data = jArray.getJSONObject(i);
ct_id=json_data.getInt("id");
ct_name=json_data.getString("name");
tv.append(ct_name);
}
}catch(JSONException e1){
// Toast.makeText(getBaseContext(), "No City Found" ,Toast.LENGTH_LONG).show();
} catch (ParseException e1) {
e1.printStackTrace();
}
}
});
}
}
答案 0 :(得分:0)
清除ArryList
中使用的任何对象的数组或ListView Adapter
。然后再次将新数据加载到Array/ArrayList
并调用adapter.notifyDataSetChanged()
方法。
答案 1 :(得分:0)
从您想要清除的代码中调用这两种方法 这里的适配器是您在列表中添加它的ArrayAdapter的一个实例。
adapter.clear()
adapter.notifyDataSetChanged()
答案 2 :(得分:0)
每次创建一个新列表并从中获取数据,并仅在此列表中添加旧数据。
答案 3 :(得分:0)
只需写下listView.setAdapter(null)
你要清除listview的地方..这对我有用..