Question

我想利用visual studio intellisense，因此我读过：

http://msdn.microsoft.com/en-us/library/bb514138.aspx

无论如何为什么我没有得到intellisense：

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

function Test() {
    /// <returns type="Customer"></returns>

    var c = new Object();
    $.ajax({
        async: false,
        dataType: "json",
        url: "Ajax/GetCustomer.aspx",
        success: function (foundCustomer) {
            // I know that found customer is of type Customer
            c = foundCustomer;
        }
    });

    return c;
}

var x = Test();
x. // No intellicense! why?

如何告诉visual studio知道该函数将返回TYPE Customer的对象？例如，如果我替换函数Test for：function Test(){ return new Customer(); }，那么intellicense将起作用。

修改

我最终的目标是：

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

Object.prototype.CastToCustomer = function(){
    /// <returns type="Customer"></returns>
    return this;
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {

        foundCustomer = foundCustomer.CastToCustomer();
        foundCustomer.// Intellicense does not work :(
    }
});

我得到了很多json对象，我想使用这个辅助函数来构建它们。

临时解决方案：

这就是我最终要做的事情：

function Customer() {
    this.Id = 0;
    this.FirstName = "";
    this.LastName = "";
}

$.ajax({
    async: false,
    dataType: "json",
    url: "Ajax/GetCustomer.aspx",
    success: function (foundCustomer) {
        // this will never be true on real browser. It is always true in visual studio (visual studio will now think that found customer is of type Customer ;)
        if (document.URL.length == 0) foundCustomer = new Customer();

        foundCustomer.// Intellisense works!!!!
    }
});

Answer 1

您正在将返回值初始化为Object，因此它位于Intellisense所基于的值上。如果您将其初始化为空Customer，那么Intellisense将检测到它正在返回Customer

function Test() {

    var c = new Customer(); //only for Intellisense

    $.ajax({...});

    return c;
}

Test(). //Customer members now appear

您还可以使用/// <param />指定参数类型：

$.ajax({
    ...

        success: function (foundCustomer) {
           /// <param name='foundCustomer' type='Customer' />
           foundCustomer. //Customer members appear            
        }
});

最后，您的document.URL.length技巧也可用于投射方法：

Object.prototype.CastToCustomer = function() {

  var c = new Customer();
  if (document.URL.length) c = this;
  return c;

}

Answer 2

如果您将Customer函数更改为接受参数：

function Customer(opts) {
    var opts = opts || {};

    this.id = 0;
    this.firstName = '';
    this.lastName = '';

    for (var i in opts) {
        if (opts.hasOwnProperty(i)) this[i] = opts[i];
    }
}

然后在Test功能中，将c = foundCustomer更改为c = new Customer(foundCustomer)。我猜这可能触发了知识产权？

创建适用于intellisense的javascript函数

修改

临时解决方案：

2 个答案: