我知道在阅读了很多答案之前已经涵盖了这个问题,他们都告诉我如何编写SQL而不是如何打印结果。
我的困境是我有一个带有付款方式字段的订单表,看起来像这样
OrderID OrderNumber PaymentMethod
1234 a1b2c3 PayPal
1235 a1b2c4 Account
1236 a1b2c5 Account
1237 a1b2c6 PayPal
1238 a1b2c7 Account
1239 a1b2c8 PayPal
1230 a1b2c9 PayPal
我需要打印出类似
的内容PayPal付款次数:4
帐户付款次数:3
我试过用这个答案
MySQL: Count occurrences of distinct values
我有这个代码
SELECT PaymentMethod,COUNT(*) as Payment FROM tablename GROUP BY PaymentMethod ORDER BY Payment DESC;
但如何打印出来?
答案 0 :(得分:1)
$returned = mysqli_query("SELECT PaymentMethod,COUNT(distinct PaymentMethod) as Payment FROM tablename GROUP BY PaymentMethod ORDER BY Payment DESC;");
while($data = mysqli_fetch_assoc($returned)){
echo "Number of " . $data['PaymentMethod'] . ": " . $data[0] . "<br>";
}
答案 1 :(得分:0)
您应该将数据表示留给VIEW。
话虽如此,这就是你如何使用纯粹的MySQL提取以这种方式格式化的数据:
SELECT concat('Number of ', paymentmethod ,' payments: ', count(*)) RESULT FROM t
GROUP BY paymentmethod
ORDER BY paymentmethod DESC
这导致:
| RESULT |
|-------------------------------|
| Number of PayPal payments: 4 |
| Number of Account payments: 3 |
小提琴here。