android如何检查服务是否正在运行

Question

我有一个可以获得GPS坐标的应用程序。它工作正常但我想在服务运行时从调用活动中进行测试。我有以下代码，我认为会检查，但当通知栏中的GPS图标仍然闪烁时，它返回false。有什么想法为什么？提前致谢

private boolean isGpsServiceRunning() {
          ActivityManager manager = (ActivityManager)getSystemService(ACTIVITY_SERVICE);
          for (RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {
            if ("LocationService".equals(service.service.getClassName())) {
              return true;
            }
          }
          return false;
        }

LocalBroadcastManager.getInstance(getApplicationContext())
                            .registerReceiver(
                                    locationChangereceiver,
                                    new IntentFilter(
                                            LocationChangeIntent.ACTION_LOCATION_CHANGE));
                    startService(new Intent(this, LocationService.class));

Answer 1

您应该与LocationService.class.getName()进行比较，而不是使用硬编码值。此外，您使用的值对应于Class#getSimpleName()，这可能不是您想要的。

Answer 2

 public boolean check(){
     ActivityManager manager = (ActivityManager) getSystemService(ACTIVITY_SERVICE);
    for (RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) 
            {
                if ("com.example.yourpackagename.YourserviceName"
                        .equals(service.service.getClassName())) 
                {
                    return true;
                }
            }
         return false;
    }

Answer 3

这种方法适用于我并且易于使用：

private boolean isMyServiceRunning() {
    ActivityManager manager = (ActivityManager) getSystemService(Context.ACTIVITY_SERVICE);

    Log.i(TAG,"MyService.class.getName() = "+ButtonOnBootService.class.getName());              

    for (RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {

        Log.i(TAG,"service.getClassName() = " +service.service.getClassName());

        if (ButtonOnBootService.class.getName().equals(service.service.getClassName())) {
            return true;
        }
    }
    return false;   
}