叫我迂腐但有没有更优雅的方式来结合所有这些检查?
SELECT * FROM [TABLE1]
WHERE [path] = 'RECEIVE'
AND [src_ip] NOT LIKE '10.48.20.10'
AND [src_ip] NOT LIKE '0.%'
AND [src_ip] NOT LIKE '127.%'
ORDER BY [date],[time] DESC;
对于这样的事情:
SELECT * FROM [TABLE1]
WHERE [path] = 'RECEIVE'
AND [src_ip] NOT LIKE IN ('10.48.20.10','0.%','127.%', .... )
ORDER BY [date],[time] DESC;
答案 0 :(得分:0)
您可以使用正则表达式。在MySQL中就像是
select * from [TABLE1]
where [path] = 'RECEIVE'
and [src_ip] not regexp '^(10\\.48\\.20\\.10$|0\\.|127\\.)'
order by [date], [time] desc
在Oracle中,它可能类似于
select * from [TABLE1]
where [path] = 'RECEIVE'
and not regexp_like([src_ip], '^(10\.48\.20\.10$|0\.|127\.)')
order by [date], [time] desc
答案 1 :(得分:0)