我在将新的pyqt5 signals and slots应用到脚本中时遇到了一些麻烦,其目的是测试/调用我一直试图解决的另一个问题,GUI冻结/崩溃......目标是这样的这些信号和插槽运行正常,GUI在运行+/- 30秒后不会崩溃,只是继续计算数字直到时间结束。我提供了一个pyqt4示例,尽管有一个pyqt5解决方案会很棒。谢谢:))
from time import sleep
import os
from PyQt4 import QtCore, QtGui, uic
from PyQt4.QtGui import *
import random
import os
import time
class Cr(QtCore.QThread):
def __init__(self):
QtCore.QThread.__init__(self)
def run(self):
while True:
rndInt = random.randint(1, 100000)
timesleep = random.random()
time.sleep(timesleep)
for i in range(120):
self.emit(QtCore.SIGNAL('host_UP'), 'foo' + str(rndInt), i)
QtGui.QApplication.processEvents()
class Main_Window(QWidget):
def __init__(self, *args):
QWidget.__init__(self, *args)
self.relativePath = os.path.dirname(sys.argv[0])
self.Main_Window = uic.loadUi("Main_Window.ui", self)
self.Main_Window.show()
self.Main_Window.move(790, 300)
self.GU = []
ProgressThreads = self.printThreads
self.details_label = []
for i in range(120):
self.details_label.insert(i, 0)
self.details_label[i] = QLabel(" ")
ProgressThreads.addWidget(self.details_label[i])
ProgressThreads.addSpacing(6)
self.details_label[i].setText(Tools.Trim.Short('Idle', 7))
self.GU.insert(i, Cr())
self.GU[i].start()
self.connect(self.GU, QtCore.SIGNAL("host_UP"), self.UpdateHost)
def UpdateHost(self, str1, pos1):
self.details_label[pos1].setText(str1)
class guiUpdate():
def GUI_main(self):
self.GUI = GUI
if __name__ == "__main__":
app = QApplication(sys.argv)
guiUpdate.GUI_main.GUI = Main_Window()
sys.exit(app.exec_())
感谢您的帮助:)
更新 下面的脚本是上面脚本的希望正确的PyQt5版本。但是,崩溃和“未响应”消息的问题仍未解决
from time import sleep
import os
from PyQt5 import QtCore, QtGui, uic
from PyQt5.QtWidgets import *
from PyQt5.QtCore import QObject, pyqtSignal
import random
import os
import time
import Tools
import sys
class Cr(QtCore.QThread):
def __init__(self, sam):
QtCore.QThread.__init__(self)
self.sam = sam
def run(self):
while True:
rndInt = random.randint(1, 100000)
timesleep = random.random()
time.sleep(timesleep)
for i in range(5):
#time.sleep(1)
self.sam.connect_and_emit_trigger('foo' + str(rndInt), i)
#self.emit(QtCore.SIGNAL('host_UP'), 'foo' + str(rndInt), i)
#QtGui.QApplication.processEvents()
class Main_Window(QWidget):
def __init__(self, *args):
QWidget.__init__(self, *args)
self.relativePath = os.path.dirname(sys.argv[0])
self.Main_Window = uic.loadUi("Main_Window.ui", self)
self.Main_Window.show()
self.Main_Window.move(790, 300)
sam = Foo()
self.GU = []
ProgressThreads = self.ProgressThreads
self.details_label = []
for i in range(5):
self.details_label.insert(i, 0)
self.details_label[i] = QLabel(" ")
ProgressThreads.addWidget(self.details_label[i])
ProgressThreads.addSpacing(6)
self.details_label[i].setText(Tools.Trim.Short('Idle', 7))
self.GU.insert(i, Cr(sam))
self.GU[i].start()
class Foo(QObject):
# Define a new signal called 'trigger' that has no arguments.
trigger = pyqtSignal()
def connect_and_emit_trigger(self, str, i):
self.str = str
self.i = i
self.trigger.connect(self.handle_trigger)
self.trigger.emit()
def handle_trigger(self):
guiUpdate.GUI_main.GUI.details_label[self.i].setText(self.str)
class guiUpdate():
def GUI_main(self):
self.GUI = GUI
if __name__ == "__main__":
app = QApplication(sys.argv)
guiUpdate.GUI_main.GUI = Main_Window()
sys.exit(app.exec_())
答案 0 :(得分:0)
使用线程的新推荐方法(以及我获得最佳结果的方法)是使用moveToThread()
而不是直接子类化QThread。简而言之:
编写一个QObject子类来完成实际工作(让我们称之为QMyWorker)。这可能看起来有点像您现有的qthread子类,使用start()
或run()
方法等。
创建QMyWorker的无父实例
创建QThread的无父实例
使用QMyWorker.moveToThread(your_thread_instance)
(我按内存检查,仔细检查doc中的API)。
致电您的QMyWorker.start()
这种方法适合我很长的工作(4GB文件等)。
答案 1 :(得分:0)
我使用QThreadPool,QRunnable与一个worker一起使用,每个线程可以使更多的worker。 很好的例子,这里有解释 https://martinfitzpatrick.name/article/multithreading-pyqt-applications-with-qthreadpool/
我的PYQT5也冻结了,现在我可以通过打印TimeStamp对其进行微调了