Question

我正在使用Spring MVC构建一个应用程序。

我首先使用webapp原型创建了一个Maven项目。

我按照教程（给出了源代码），我找不到我错在哪里？教程url：http://www.mkyong.com/spring3/spring-3-mvc-hello-world-example/

这是我的项目树：

Project tree

我的pom.xml：

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>com.j2ee</groupId>
    <artifactId>theaterJ2ee</artifactId>
    <packaging>war</packaging>
    <version>0.1</version>
    <name>j2ee Maven Webapp</name>
    <url>http://maven.apache.org</url>

    <dependencies>
        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>4.11</version>
        </dependency>
        <dependency>
            <groupId>org.apache.derby</groupId>
            <artifactId>derby</artifactId>
            <version>10.10.1.1</version>
        </dependency>

        <!-- LOGGER -->
        <dependency>
            <groupId>log4j</groupId>
            <artifactId>log4j</artifactId>
            <version>1.2.17</version>
        </dependency>

        <!-- Spring MVC -->
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>servlet-api</artifactId>
            <version>2.5</version>
            <type>jar</type>
            <scope>compile</scope>
        </dependency>

        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-core</artifactId>
            <version>3.2.4.RELEASE</version>
        </dependency>

        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-web</artifactId>
            <version>3.2.4.RELEASE</version>
        </dependency>

        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-webmvc</artifactId>
            <version>3.2.4.RELEASE</version>
        </dependency>

    </dependencies>
    <build>
        <finalName>theaterJ2ee</finalName>
        <plugins>
            <plugin>
                <artifactId>maven-compiler-plugin</artifactId>
                <configuration>
                    <source>1.6</source>
                    <target>1.6</target>
                </configuration>
            </plugin>
        </plugins>
    </build>
</project>

web.xml：

<web-app id="WebApp_ID" version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Spring Web MVC Application</display-name>

    <servlet>
        <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

</web-app>

MVC-调度-servlet.xml中

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <context:component-scan base-package="com.j2ee.controllers" />

    <bean
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix">
            <value>/WEB-INF/pages/</value>
        </property>
        <property name="suffix">
            <value>.jsp</value>
        </property>
    </bean>

</beans>

我做的控制器：

package com.j2ee.controllers;

import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;

@Controller
@RequestMapping("/welcome")
public class HelloController
{
    @RequestMapping(method = RequestMethod.GET)
    public String printWelcome(final ModelMap model)
    {
        // we will access this attribute in the page using ${messageToPrint}
        model.addAttribute("messageToPrint", "This is a TEST.");
        model.addAttribute("message2", "hi!");
        // Will show the /WEB-INF/pages/test.jsp
        return "hello";
    }
}

我正在尝试访问页面theaterj2ee / welcome并且它不起作用（资源无法访问）。

我把webapp放在eclipse下的tomcat上。

当我在tomcat上运行我的项目和教程项目时，只能访问教程..

Answer 1

解决方案的想法：

在web.xml中替换

<servlet-mapping>
    <servlet-name>mvc-dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

通过

<servlet-mapping>
     <servlet-name>mvc-dispatcher</servlet-name>
     <url-pattern>*.htm</url-pattern>
</servlet-mapping>

看看什么项目： https://github.com/ctesniere/ColisExpress/

Answer 2

您需要从控制器返回ModelAndView而不是String ......视图解析器将解析视图.......

创建新的ModelAndView（）对象...在模型中设置数据并设置视图名称。

有关弹簧控制器的教程，请参阅http://www.baeldung.com/spring-controllers

Spring MVC无法在Tomcat上访问应用程序

2 个答案: