我想使用google api创建gmail用户帐户。我正在向服务器发送JSON请求以获取授权代码,但我在httpwebresponse中收到了这些错误: -
异常详细信息:System.Net.WebException:远程服务器返回错误:(400)错误请求
var request = (HttpWebRequest)WebRequest.Create(@"https://accounts.google.com/o/oauth2/auth");
request.Method = "POST";
request.ContentType = "text/json";
request.KeepAlive = false;
//request.ContentLength = 0;
using (StreamWriter streamWriter = new StreamWriter(request.GetRequestStream()))
{
string json = "{\"scope\":\"https%3A%2F%2Fwww.googleapis.com%2Fauth%2Fuserinfo.email+https%3A%2F%2Fwww.googleapis.com%2Fauth%2Fuserinfo.profile\"," + "\"state\":\"%2Fprofile\"," + "\"redirect_uri\":\"http://gmailcheck.com/response.aspx\"," + "\"response_type\":\"code\"," + "\"client_id\":\"841994137170.apps.googleusercontent.com\"}";
streamWriter.Write(json);
// streamWriter.Flush();
//streamWriter.Close();
}
using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
{
StreamReader responsereader = new StreamReader(response.GetResponseStream());
var responsedata = responsereader.ReadToEnd();
//Session["responseinfo"] = responsereader;
//testdiv.InnerHtml = responsedata;
}
}
答案 0 :(得分:11)
一旦你得到一个例外,你必须从服务器读取实际的响应,应该有一些有用的东西。像错误描述或扩展状态代码......
For Instance:
try
{
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
... your code goes here....
}
catch (WebException ex)
{
using (WebResponse response = ex.Response)
{
var httpResponse = (HttpWebResponse)response;
using (Stream data = response.GetResponseStream())
{
StreamReader sr = new StreamReader(data);
throw new Exception(sr.ReadToEnd());
}
}
}