def ticketdo(tickethave):
phrase = "Your total is $"
if tickethave == "n":
print phrase + "22"
elif tickethave != "n":
tickethour = input("How long has your car been parked?")
if tickethour <=1:
print phrase + "2"
elif tickethour <=2:
print phrase + "4"
elif tickethour <=3:
print phrase + "6"
elif tickethour <=4:
print phrase + "8"
elif tickethour <=5:
print phrase + "10"
elif tickethour <=6:
print phrase + "12"
elif tickethour <=7:
print phrase + "14"
elif tickethour <=8:
print phrase + "16"
elif tickethour > 8:
print phrase + "20"
def main():
tickethave = raw_input("Do you have your ticket? (y/n): ")
print ticketdo(tickethave)
main()
答案 0 :(得分:3)
这是因为ticketdo
没有返回任何内容。默认情况下,不返回任何内容的函数返回None
。这是因为,在Python中,所有函数都必须返回某些东西。
此外,通过:
print ticketdo(tickethave)
你告诉Python打印ticketdo
的返回值。
因此,要解决此问题,请将print
放在该行上或让ticketdo
返回一些内容然后打印出来(根据您的代码结构判断,您可能需要第一个解决方案)。< / p>
答案 1 :(得分:0)
您正在打印ticketdo
功能的返回值。由于您没有明确指定该函数的返回值,因此它将自动返回默认值None
,这正是您要打印到stdout的内容。
如果你想简单地调用函数而不打印它的返回值,只需执行:
ticketdo(tickethave)
调用函数时,不需要对函数的返回值执行任何操作。使用返回值完全是可选的。
答案 2 :(得分:-1)
我只是在ticketdo(tickethave)
之前删除了打印:
#!/usr/bin/env python
def ticketdo(tickethave):
phrase = "Your total is $"
if tickethave == "n":
print phrase + "22"
elif tickethave != "n":
tickethour = input("How long has your car been parked?")
if tickethour <=1:
print phrase + "2"
elif tickethour <=2:
print phrase + "4"
elif tickethour <=3:
print phrase + "6"
elif tickethour <=4:
print phrase + "8"
elif tickethour <=5:
print phrase + "10"
elif tickethour <=6:
print phrase + "12"
elif tickethour <=7:
print phrase + "14"
elif tickethour <=8:
print phrase + "16"
elif tickethour > 8:
print phrase + "20"
def main():
tickethave = raw_input("Do you have your ticket? (y/n): ")
ticketdo(tickethave)
if __name__ == "__main__":
main()