Question

请帮忙撰写查询。

我有三张桌子：

+-------------------+
| Patient           |
| PatientPhysician  |
| Physician         |
+-------------------+

在 PhysicianOrganizationId 中找到 FirstName ， LastName 和 DoB 的患者是相似的。

我将向您展示您更好地理解问题的数据：

    mysql> SELECT pt.Id, pt.FirstName, pt.LastName, pt.DoB, ph.PhysicianOrganizationId
        -> FROM Patient pt, Physician ph, PatientPhysician pp
        -> WHERE pt.Id = pp.IdPatient AND ph.Id = pp.IdPhysician
        -> ORDER BY pt.Id;

+----+-----------+-------------+------------+-------------------------+
| Id | FirstName | LastName    | DoB        | PhysicianOrganizationId |
+----+-----------+-------------+------------+-------------------------+
|  1 | Mario     | Gotze       | 1989-01-09 |                     101 |
|  2 | Mario     | Gotze       | 1989-01-09 |                     102 |
|  3 | Mario     | Gotze       | 1989-01-09 |                     101 |
|  4 | Fillip    | Gotze       | 1989-01-09 |                     101 |
|  5 | Marco     | Rues        | 1988-09-12 |                     102 |
|  5 | Marco     | Rues        | 1988-09-12 |                     101 |
|  5 | Marco     | Rues        | 1988-09-12 |                     103 |
|  6 | Dimitri   | Payet       | 1986-10-10 |                     101 |
|  7 | Dimitri   | Payet       | 1986-10-10 |                     101 |
|  8 | Dimitri   | Payet       | 1986-10-10 |                     101 |
|  8 | Dimitri   | Payet       | 1986-10-10 |                     102 |
|  9 | Zlatan    | Ibrahimovic | 1982-01-12 |                     103 |
|  9 | Zlatan    | Ibrahimovic | 1982-01-12 |                     101 |
| 10 | Zlatan    | Ibrahimovic | 1982-01-12 |                     101 |
| 10 | Zlatan    | Ibrahimovic | 1982-01-12 |                     103 |
+----+-----------+-------------+------------+-------------------------+
15 rows in set (0.01 sec)

我写了一个查询，但结果不正确：

SELECT
    pt.Id,
    pt.FirstName,
    pt.LastName,
    pt.DoB,
    ph.PhysicianOrganizationId

FROM Patient pt, Physician ph, PatientPhysician pp

WHERE pt.Id = pp.IdPatient AND ph.Id = pp.IdPhysician

GROUP BY pt.FirstName, pt.LastName, pt.DoB, ph.PhysicianOrganizationId

HAVING COUNT(*) > 1 ORDER BY pt.Id;

结果：

+----+-----------+-------------+------------+-------------------------+
| Id | FirstName | LastName    | DoB        | PhysicianOrganizationId |
+----+-----------+-------------+------------+-------------------------+
|  1 | Mario     | Gotze       | 1989-01-09 |                     101 | 
|  6 | Dimitri   | Payet       | 1986-10-10 |                     101 | 
|  9 | Zlatan    | Ibrahimovic | 1982-01-12 |                     103 |
|  9 | Zlatan    | Ibrahimovic | 1982-01-12 |                     101 |
+----+-----------+-------------+------------+-------------------------+

我需要这个结果：

+----+-----------+-------------+------------+-------------------------+
| Id | FirstName | LastName    | DoB        | PhysicianOrganizationId |
+----+-----------+-------------+------------+-------------------------+
|  1 | Mario     | Gotze       | 1989-01-09 |                     101 |
|  3 | Mario     | Gotze       | 1989-01-09 |                     101 |
|  6 | Dimitri   | Payet       | 1986-10-10 |                     101 |
|  7 | Dimitri   | Payet       | 1986-10-10 |                     101 |
|  8 | Dimitri   | Payet       | 1986-10-10 |                     101 |
|  9 | Zlatan    | Ibrahimovic | 1982-01-12 |                     103 |
|  9 | Zlatan    | Ibrahimovic | 1982-01-12 |                     101 |
| 10 | Zlatan    | Ibrahimovic | 1982-01-12 |                     103 |
| 10 | Zlatan    | Ibrahimovic | 1982-01-12 |                     101 |
+----+-----------+-------------+------------+-------------------------+

告诉我我做错了什么？

Answer 1

SELECT pt.Id, tmp1.fname, tmp1.lname, tmp1.dob, tmp1.poid

FROM (

  SELECT pt.FirstName AS fname,
         pt.LastName AS lname,
         pt.DoB as dob,
         ph.PhysicianOrganizationId AS poid

  FROM Patient pt, Physician ph, PatientPhysician pp

  WHERE pt.Id = pp.IdPatient AND ph.Id = pp.IdPhysician

  GROUP BY fname, lname, dob, poid

  HAVING COUNT(*) > 1) AS tmp1

JOIN Patient AS pt ON pt.FirstName = tmp1.fname AND pt.LastName = tmp1.lname AND pt.DoB = tmp1.dob

JOIN PatientPhysician AS pp ON pt.Id = pp.IdPatient

JOIN Physician AS ph ON ph.Id = pp.IdPhysician AND tmp1.poid = ph.PhysicianOrganizationId

ORDER BY pt.Id;

Answer 2

尝试将pt.Id添加到您的GROUP BY子句：

SELECT
    pt.Id,
    pt.FirstName,
    pt.LastName,
    pt.DoB,
    ph.PhysicianOrganizationId
FROM
    Patient pt,
    Physician ph,
    PatientPhysician pp
WHERE
    pt.Id = pp.IdPatient
AND ph.Id = pp.IdPhysician
GROUP BY
    pt.Id,
    pt.FirstName,
    pt.LastName,
    pt.DoB,
    ph.PhysicianOrganizationId
HAVING COUNT(*) > 1
ORDER BY pt.Id;

N.B。我还没有测试过上面的SQL

MySQL ManyToMany显示重复的行

2 个答案: